4(0.5x+2.5y-0.7x-1.3y+4)
2 answers:
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Answer:
Probability that component 4 works given that the system is functioning = 0.434 .
Step-by-step explanation:
We are given that a parallel system functions whenever at least one of its components works.
There are parallel system of 5 components and each component works independently with probability 0.4 .
Let <em>A = Probability of component 4 working properly, P(A) = 0.4 .</em>
<em>Also let S = Probability that system is functioning for whole 5 components, P(S)</em>
Now, the conditional probability that component 4 works given that the system is functioning is given by P(A/S) ;
P(A/S) = {Means P(component 4 working and system also working)
divided by P(system is functioning)}
P(A/S) = {In numerator it is P(component 4 working) and in
denominator it is P(system working) = 1 - P(system is not working)}
Since we know that P(system not working) means that none of the components is working in system and it is given with the probability of 0.6 and since there are total of 5 components so P(system working) = 1 - .
Hence, P(A/S) = = 0.434.
Answer:
the third side is 4.
Step-by-step explanation:
Using Pythagorean theorem of a^2 + b^2 = c^2 for right triangles, substitute
the numbers to show ( +
=
and solve for b. The square root and square cancel each other out, so you get 65 +
= 81.
Subtract 65 from both sides to get = 16.
Then take the square root of both sides to get b = which equals 4.