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3 years ago

What is the equation of a circle with center 8,6 and radius 5

Mathematics

2 answers:

WINSTONCH [101]3 years ago

6 0

(x - 8)² + (y - 6)² = 5²
(x - 8)² + (y - 6)² = 25 ← answer

Fantom [35]3 years ago

5 0

The answer is (x - 8)² + (y - 6)² = 25

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Jose purchased 4/9 pound of peanut and 7/11 pounds of raisins find the total weight of his purchase

azamat

Answer:

The total weight of his purchase is 1.08 pounds

Step-by-step explanation:

To find the total weight of his purchase, we sum the weight of each of his purchases.

He purchased:

4/9 pound of peanut.

7/11 pounds of raisins

Total:

The least common multiple between 9 and 11 is 99.

Then

$\frac{4}{9} + \frac{7}{11} = \frac{11*4 + 9*7}{99} = \frac{107}{99} = 1.08$

The total weight of his purchase is 1.08 pounds

8 0

3 years ago

If the base of a right angle triangle is 8 cm and the hypotenuse is 17 cm find its area.

damaskus [11]

The area of the triangle is 60 cm

6 0

3 years ago

Read 2 more answers

Show me how to make 33 in four different ways

tamaranim1 [39]

30+3
11*3
10*3+3
60-30+3

(sorry if these didn't help i'm a beginner and i'm in 7th grade)

7 0

3 years ago

2a ³+10=26 Show the work on how you got it

Usimov [2.4K]

Answer:

a=2

Step-by-step explanation:

subtract 10 from both sides

2a^3=26-10

simplify

2a^3=16

Divivde both side by 2

a^2=16/2

simplify

a^3=8

4 0

3 years ago

A hog producer is feeding soybean meal and corn to his pigs. He needs to know how many pounds he needs to feed of each in order

Mazyrski [523]

Answer:

Feed 1, Soybean meal required = $\dfrac{2000}{3} \text{ lbs.}$

Feed 2, Corn meal required = $\dfrac{4000}{3} \text{ lbs.}$

Step-by-step explanation:

Total feed is 1 ton i.e. 2000 lbs.

Let x be the amount of Feed 1 required.

Feed 1 has $45\%$ of protein.

$\text{Protein in Feed 1 = }x \times \dfrac{45}{100} ..... (1)$

Then, amount of Feed 2 required = $(2000 - x) \text{ lbs.}$

Feed 2 has $15\%$ of protein.

$\text{Protein in Feed 2 = }(2000 - x) \times \dfrac{15}{100} ..... (2)$

As per question, total protein required is $25\%$ of 2000 lbs .

Adding (1) and (2) and putting it equal to total protein required.

$\Rightarrow x \times \dfrac{45}{100} + (2000 - x) \times \dfrac{15}{100} = 2000 \times \dfrac{25}{100}\\\Rightarrow 45x + 30000 - 15x = 50000\\\Rightarrow 30x = 20000\\\Rightarrow x = \dfrac{2000}{3}$

Feed 1 required = $\dfrac{2000}{3}\text{ lbs .}$

Feed 2 required = $2000 - \dfrac{2000}{3}\\$

$\Rightarrow \dfrac{4000}{3}\text{ lbs.}$

7 0

3 years ago