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babunello [35]
3 years ago
14

Which of the following is the result of expanding 4 £ n=1 (2n-3)

Mathematics
1 answer:
geniusboy [140]3 years ago
3 0

Answer: 8

Step-by-step explanation: the given expression is 2n-3

so when n=1, we will get, 2(1)-3=2-3=-1

when n=2, we will get, 2(2)-3= 4-3=-1

when n=3, we will get 2(3)-3= 6-3=3

when n=4, we will get 2(4)-3 = 8-3=5

so the required result of expansion is -1+1+3+5=8

answer is 8.

hope that helped!

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The population of a city increases by 5% every year. If it’s population today is 300,000 what will it’s population be in 2 years
disa [49]

Answer:

Population after n years = Present Population =(1+

100

r

​

)

n

Population after 2 years =50000(1+

100

5

​

)

2

=50000(

100

105

​

)

2

=50000×

100

105

​

×

100

105

​

=5×105×105=55125

Step-by-step explanation:

6 0
2 years ago
Anyone know this question?<br><br>Just B please
Gre4nikov [31]

Answer:

52% and 7

Step-by-step explanation:

There are 25 squares of which 13 are shaded , then

\frac{13}{25} × 100% = 13 × 4% = 52°

(b)

1 square represents \frac{1}{25} × 100% = 1 × 4% = 4%

Then 80% = 80% ÷ 4% = 20

That is for 80% , 20 squares require to be shaded

That is 7 more than the 13 already shaded

4 0
3 years ago
Pls help i’ll give u a brainlest
goblinko [34]

Answer:

(13×14×6)/3= 364 centimeter cube

I answered wrongly cuz forgot to divide by 3

my mistake

7 0
3 years ago
Read 2 more answers
4000
Airida [17]

Answer:

$1000 ; 500 ; 1000 ; y = 500x + 1000

Step-by-step explanation:

From the graph, the initial deposit which started the savings account is $1000 ; this is the value on the y - intercept, the value in the account at time or period = 0.

The slope :

x1 = 0 ; y1 = 1000

x2 = 6 ; y2 = 4000

Slope = Rise / Run

Rise = y2 - y1 = 4000 - 1000 = 3000

Run = x2 - x1 = 6 - 0 = 6

Hence,

Slope = 3000 / 6

Slope = 500

y - intercept = 1000 (from. Graph)

Equation in slope intercept form:

General form : y = mx + c

m = slope ; c = intercept

Equation is written as ;

y = 500x + 1000

5 0
3 years ago
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
2 years ago
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