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alekssr [168]
2 years ago
7

You need a 50% solution. On hand, you have a 200 mL of a 35% alcohol mixture. You also have 70% alcohol mixture. How much of the

70% mixture will you need to add to obtain the desired solution?
Mathematics
1 answer:
CaHeK987 [17]2 years ago
6 0

Answer:

150 mL

Step-by-step explanation:

We need a mixture that is at 50%, now we have 200 mL at 35% and another mixture that is at 70%, that is, we must calculate how much of this mixture is added, by the following equation

200 * 35% + x * 70% = 50% (x + 200)

70 + 0.7 * x = 0.5 * x + 100

0.7 * x - 0.5 * x = 100 - 70

0.2 * x = 30

x = 30 / 0.2

x = 150

150 mL must be added so that the mixture is 50%.

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Find the second partial derivatives of the following functions
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has first-order partial derivatives

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(b) <em>z</em> = 4<em>x</em> <em>eʸ</em>

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∂<em>z</em>/∂<em>y</em> = 4<em>x</em> <em>eʸ</em>

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∂²<em>z</em>/∂<em>y</em>∂<em>x</em> = 4<em>eʸ</em>

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<em />

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Step two: Add 4 to both sides of the equation. When you do this step, your problem should look like this:

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Step four: Wrap-up. What the answer is.

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Final step: OUR ANSWER!

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Hope this helped! :D

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