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liraira [26]
3 years ago
15

the area of a desktop is represented by x^2 - 49. find the dimensions of the desktop in terms of x. show work please.​

Mathematics
1 answer:
Levart [38]3 years ago
4 0

Answer:

The dimensions of the desktop are (x+7) units by (x-7) units

Step-by-step explanation:

we know that

The difference of squares is equal to

a^2-b^2=(a+b)(a-b)

we have

x^2-49

Remember that

49=7^2

substitute

x^2-7^2

Applying difference of squares

x^2-7^2=(x+7)(x-7)

therefore

The dimensions of the desktop are (x+7) units by (x-7) units

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Please solve and explain the question below
solong [7]

Answer:

OPTION A

Step-by-step explanation:

To find the table substitute the points on the given function and compare the values.

The given function is: $ y = x^2 + 2 $.

OPTION A:

(i) When x = -2

LHS = y = 6.

RHS = (-2)² + 2 = 4 + 2 = 6.

LHS = RHS

(ii) When x = -1

LHS = y = 3

RHS = (-1)² + 2 = 1 + 2 = 3.

LHS = RHS

(iii) When x = 0

LHS = y = 2

RHS = 0² + 2 = 2.

LHS = RHS

(iv) When x = 1

LHS = y = 3

RHS = (1)² + 2 = 1 + 2 = 3.

LHS = RHS

(v) When x = 2

LHS = y = 6

RHS = (2)² + 2 = 4 + 2 = 6

LHS = RHS

OPTION B:

(i) When x = -2

LHS = y = -2

RHS = (-2)² + 2 = 6

LHS \neq RHS

OPTION B is eliminated.

OPTION C:

(i) When x = -2

Using the same reason as OPTION B this option is eliminated as well.

So, OPTION A is the correct answer.

5 0
3 years ago
Round 9.42 to one decimal place
klasskru [66]
The answer would be 9
6 0
3 years ago
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There are 8 swimmers in the swimming club. The club bought c swimming caps to split among its members. Write an expression that
love history [14]

Answer:

c/8

Step-by-step explanation:

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2 years ago
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Uzanne can work 10 math problems in 15 minutes. How many can she work in an hour and a half?
jeyben [28]
1 and half hour
= 60 minutes+ 30 minutes
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Now,

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4 0
3 years ago
If x= sin theta then x/√1-x^2 is​
SCORPION-xisa [38]

Well,

Given that x=\sin(\theta),

We can rewrite the equation like,

\dfrac{\sin(\theta)}{\sqrt{1-\sin(\theta)^2}}

Now use, \cos(\theta)^2+\sin(\theta)^2=1 which implies that 1-\sin(\theta)^2=\cos(\theta)^2

That means that,

\dfrac{\sin(\theta)}{\sqrt{1-\sin(\theta)^2}}\Longleftrightarrow\dfrac{\sin(\theta)}{\sqrt{\cos(\theta)^2}}

By def \sqrt{x^2}=x therefore \sqrt{\cos(\theta)^2}=\cos(\theta)

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\boxed{\tan(\theta)}=\dfrac{\sin(\theta)}{\cos(\theta)}

Hope this helps.

r3t40

6 0
3 years ago
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