Anything 5 and up, because when you multiply the by 15, they equal more than 65, making the inequality true.
Answer:
the slope of the regression equation for predicting our Exam 2 scores from Exam 1 scores is 0.492
And the y-intercept of the regression equation for predicting our Exam 2 scores from Exam 1 is 33.688
Step-by-step explanation:
Given the data in the question;
mean X" = 86
SD σx = 10
Y" = 76
SD σy = 8.2
r = 0.6
Here, Exam 2 is dependent and Exam 1 is independent.
The Regression equation is
y - Y" = r × σy/σx ( x - x" )
we substitute
y - 76 = 0.6 × 8.2/10 ( x - 86 )
y - 76 = 0.492( x - 86 )
y - 76 = 0.492x - 42.312
y = 0.492x - 42.312 + 76
y = 0.492x + 33.688
Hence, the slope of the regression equation for predicting our Exam 2 scores from Exam 1 scores is 0.492
And the y-intercept of the regression equation for predicting our Exam 2 scores from Exam 1 is 33.688
Yes for the first and last the middle one should also be x^2+4
If you have the area of the rectangle, then the equation would be A = W*L
Lets say the area is 15 and the width is 3. You don't know what the length is. Just divide 3 into 15 to get 5. Hope this helps!
Answer:
28.9 feet
Step-by-step explanation:
From the above question, we have obtained the following values:
Major axis of elliptical chamber = 30 feet
Note that length of the major axis of an elliptical chamber = 2a
Hence, 2a = 30
a = 30/2
a = 15 feet
Focus or foci = c = 4 feet
Length of the minor axis =2b = ??
The formula =
c² = a² - b²
b² = a² - c²
b²= 15² - 4²
b² = 225 - 16
b² = 209
b = √209
b = 14.456832295 feet
How far out from the center along he minor axis should he built his whisper chamber = Length of the minor axis
= 2 × b
= 2 × 14.456832295 feet
= 28.91366459 feet
Approximately = 28.9 feet
