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Sphinxa [80]
3 years ago
12

Select all the graphs that are proportional.help me please​

Mathematics
2 answers:
Vaselesa [24]3 years ago
8 0
Maybe u should study i know its hard but try ur best :)
max2010maxim [7]3 years ago
7 0
I Think it’s b skisjejsjd
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A parabolic arch has a height of 25 feet and a span of 40 feet. How high is the arch 8 feet from each side of the center?
Llana [10]

Answer:

The correct option is;

21 ft

Step-by-step explanation:

The equation of the parabolic arc is as follows;

y = a(x - h)² + k

Where the height is 25 ft and the span is 40 ft, the coordinates of the vertex (h, k) is then (20, 25)

We therefore have;

y = a(x - 20)² + 25

Whereby the parabola starts from the origin (0, 0), we have;

0 = a(0 - 20)² + 25

0 = 20²a + 25 → 0 = 400·a + 25

∴a = -25/400 = -1/16

The equation of the parabola is therefore;

y = (-\frac{1}{16})(x-20)^2 + 25

To find the height 8 ft from the center, where the center is at x = 20 we have 8 ft from center = x = 20 - 8 = 12 or x = 20 + 8 = 28

Therefore, plugging the value of x = 12 or 28 in the equation for the parabola gives;

y = (-\frac{1}{16})(12-20)^2 + 25 = (-\frac{1}{16})(-8)^2 + 25 = 21 \ ft.

4 0
3 years ago
Determine the simple interest when: principal: $205,435 interest rate: 2.8%, time: 15 year
Vesna [10]
<h2>$86282.7</h2>

<em>Step-by-step explanation:</em>

<h3><em>p</em><em>r</em><em>i</em><em>n</em><em>c</em><em>i</em><em>p</em><em>l</em><em>e</em><em> </em><em>(</em><em>p</em><em>)</em><em> </em><em>=</em><em> </em><em>$</em><em>2</em><em>0</em><em>5</em><em>,</em><em>4</em><em>3</em><em>5</em></h3><h3><em>r</em><em>a</em><em>t</em><em>e</em><em> </em><em>(</em><em>r</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>8</em><em>%</em></h3><h3><em>t</em><em>i</em><em>m</em><em>e</em><em> </em><em>(</em><em>t</em><em>)</em><em> </em><em>=</em><em> </em><em>1</em><em>5</em><em> </em><em>y</em><em>e</em><em>a</em><em>r</em><em>s</em></h3><h3><em>s</em><em>i</em><em>m</em><em>p</em><em>l</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>e</em><em>r</em><em>e</em><em>s</em><em>t</em><em> </em><em>=</em><em> </em><em>(</em><em>p</em><em> </em><em>×</em><em> </em><em>r</em><em> </em><em>×</em><em> </em><em>t</em><em>)</em><em> </em><em>÷</em><em> </em><em>1</em><em>0</em><em>0</em></h3><h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>(</em><em>2</em><em>0</em><em>5</em><em>,</em><em>4</em><em>3</em><em>5</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>8</em><em> </em><em>×</em><em> </em><em>1</em><em>5</em><em>)</em><em> </em><em>÷</em><em> </em><em>1</em><em>0</em><em>0</em></h3><h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>8,628,270</em><em> </em><em>÷</em><em> </em><em>1</em><em>0</em><em>0</em></h3><h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>8</em><em>6</em><em>2</em><em>8</em><em>2</em><em>.</em><em>7</em></h3>

<h2>MARK ME AS BRAINLIST</h2><h2>PLZ FOLLOW ME</h2>
4 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
The fith term of a G.P is 8 times the 2nd term find its common ratio​
Dovator [93]

Answer:

Common ratio r = 2

Step-by-step explanation:

\because the fith term of a G.P is 8 times the 2nd term.

\therefore  \: t_5 = 8\times t_2 \\ \therefore  \: ar^{5-1}=8\times \: ar^{2-1}  \\ \therefore  \: r^{4}=8\times \: r^{1} \\ \therefore  \: r^{3}=8 \\ \therefore  \:r^{3}= {2}^{3}  \\   \hspace{20 pt}\huge \red{ \boxed{\therefore  \:r= {2}}} \\

Hence, common ratio is 2.

6 0
3 years ago
Read 2 more answers
A slope of 0.5 with an x-intercept of (28,0)
quester [9]

Step-by-step explanation:

m/slope=0.5

(28,0)

y=mx+b

0=0.5(28)+b

0=14+b

-14=b

y=0.5x -14

8 0
3 years ago
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