Slope is - 3 And (0,-4) is on the line
2 answers:
The equation of a line that has slope m and passes through the point (x1,y1) is
y-y1=m(x-x1)
given
slope=-3
point=(0,-4)
x1=0
y1=-4
equaton is
y-(-4)=-3(x-0)
y+4=-3(x)
y+4=-3x
I hope this helps you
x'=0 y'= -4
slope (x'-x)=y'-y
-3. (0-x)= -4-y
-3.-x= -4-y
3x= -4-y
y= -3x-4
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