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Sunny_sXe [5.5K]
3 years ago
9

The legs of an isosceles right triangle both measure 10 inches. Find the length of the hypotenuse.

Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

14.14

Step-by-step explanation:

10^2 + 10^2 = c^2

100 + 100 = c^2

200 = c^2

c = 14.14

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Find the circumference of a a cirele with a di<br>of 56 yards.
saw5 [17]
2πr= c

So π=3.14

56÷2= 28

2 x 3.14 x 28=c

87.12 x 2 = 174.24

The circumference is 174.24
6 0
3 years ago
Equation of a line with an slope of 1/2 that contains (-4, 7)
nasty-shy [4]

Equation of a line with an slope of 1/2 that contains (-4, 7) is y=\frac{1}{2} x+9

<em><u>Solution:</u></em>

We have been given a point and slope of an equation and have been asked to write it in an equation. The two forms of writing a point and slope in equation are point slope form and standard form.

The standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers. The standard form of a line is just another way of writing the equation of a line.

To write in standard form we will first write it in point slope form and then rearrange it into a standard from.

<em><u>The formula for point slope form:</u></em>

y-y_{1}=m\left(x-x_{1}\right)

where "m" is the slope of line

Given that "m" = \frac{1}{2} and (x_1, y_1) = (-4, 7)

\begin{array}{l}{y-7=\frac{1}{2}(x-(-4))} \\\\ {y-7=\frac{1}{2}(x+4)} \\\\ {y-7=\frac{1}{2} x+2} \\\\ {y=\frac{1}{2} x+9}\end{array}

Now, let us convert this equation to standard form

0.5x + 9 = y

0.5x - y = -9

Thus we have found out equation of line in point slope and standard form

3 0
4 years ago
Sheldon harvests the strawberries and tomatoes in his garden.
shtirl [24]

Answer:

A. 3 13/20

B.3.8 kg

C.Strawberries

Step-by-step explanation:

In order to solve this we just need to find the amount of strawberries he picked, and if he picked 1 2/5 less in the morning and in the morning he picked 2 1/4, we just add that up to know how much he picked in the afternoon:

1\frac{2}{5}+ 2\frac{1}{4}\\1 \frac{2(4)}{20}+ 2\frac{1(5)}{20}\\1 \frac{8}{20}+ 2\frac{5}{20}\\\\3\frac{13}{20}

So in the afternoon he picked 3\frac{13}{20}.

Now he picked 5 3/10 kg of tomatoes but 1.5 were rotten, we just have to withdraw the rotten from the total:

5\frac{3}{10} -1\frac{1}{2} \\5\frac{3}{10} -1\frac{5}{10} \\4\frac{3-5}{10} \\3\frac{13-5}{10} \\3\frac{8}{10}

So now we know that he picked 3\frac{8}{10} kg of good tomatoes.

If he picked in the afternoon and the morning 5.05 kg of strawberries, he picked more strawberries than tomatoes.

7 0
3 years ago
The recommended weight of a soccer ball is 430 g the actual away is allowed to vary by up to 20 g what is the minimum and maximu
amid [387]

Answer:

the minimum is 410, the max is 450

Step-by-step explanation:

to find the minimum you would do 430-20 and the max would be 430+20

8 0
3 years ago
Two runners in a marathon determine that the angles of elevation of a news helicopter are 39.5 degrees and 42 degrees. If the he
Liula [17]
See the attached figure to understand the problem

we know that
tan 42°=1950/BO---------> BO=1950/tan 42°-------> BO=2165.69 ft

tan 39.5°=1950/AO---------> AO=1950/tan 39.5°-------> AO=2365.54 ft

AB=AO-BO--------> AB=2365.54 ft-2165.69 ft-------> AB=199.85 ft

the answer is
The runners are 199.85 feet apart

8 0
3 years ago
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