All categories

3 years ago

86,678 rounded the nearest ten thousand

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

7 0

90,000 is the answer. have a great day!!

You might be interested in

Solve. −43x+16<79 Drag and drop a number or symbol into each box to show the solution.

Debora [2.8K]

The answer is the third one

7 0

3 years ago

Read 2 more answers

Given:angleONL congruent to angleMLN, angleO and angleM are right angles.

Harrizon [31]

ok so hi im elizabeth can i help you

8 0

3 years ago

Which of the following values have 2 significant figures? Check all that apply.

katen-ka-za [31]

Answer:

i would say B/90

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is 649,284,143 rounded to the nearest hundred million

zysi [14]

The answer is 600,000,000

4 0

3 years ago

P (6,6) y=2/3x

matrenka [14]

Answer:

$y = -\frac{3}{2}x+15$

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

$y = \frac{2}{3}x$

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

$y = \frac{2}{3}x$

Now, we compare the given equation by standard form $y = mx +c$

So, slope of the line $m_{1} = \frac{2}{3}$ , and

y-intercept $c=0$

We know that the slope of the perpendicular line $m_{1}\times m_{2} = -1$

$m_{2}=-\frac{1}{m_{1}}$

$m_{2}=-\frac{1}{\frac{2}{3} }$

$m_{2}=-\frac{3}{2}$

So, the slope of the perpendicular line $m_{2}=-\frac{3}{2}$

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

$y=mx+c$

Substitute point $P(x_{1}, y_{1})=P(6, 6)$ and $m = m_{2}=-\frac{3}{2}$

$6=-\frac{3}{2}\times 6 +c$

$6=-3\times 3 +c$

$c=6+9$

$c=15$

So, the y-intercept of the perpendicular line $c=15$

Using point slope formula.

$y=mx+c$

Substitute $m = m_{2}=-\frac{3}{2}$ and $c=15$ in above equation.

$y = -\frac{3}{2}x+15$

Therefore: the equation of the perpendicular line $y = -\frac{3}{2}x+15$

8 0

4 years ago