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MatroZZZ [7]
3 years ago
9

86,678 rounded the nearest ten thousand

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0
90,000 is the answer. have a great day!!
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(b+3)/7=(b-3)/6 What number = B?
poizon [28]
<span>(b+3)/7=(b-3)/6
6(b+3) = 7 (b-3)....> cross multiply
6b + 18 = 7b -21 ...>distributive property
6b - 7b = -21 -18 ...>subtract 7b to both sides then simplify
-b = -39 ...> multiply -1 to both sides
 b = 39</span>
6 0
3 years ago
Suppose that an individual has a body fat percentage of 15.6% and weighs 156 pounds. How many pounds of his weight is
ella [17]

Answer:

Percent or percentage or

%

means "per 100" or "out of 100". Therefore

12.3

%

=

12.3

100

.

So 12.3% of 129 pounds is:

12.3

100

⋅

129

1586.7

100

15.867

hops this help ✨

6 0
2 years ago
What is the area of a triangle with base of 20 feet and a vertical height
VashaNatasha [74]

Answer:

A = 400 ft²

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the vertical height ) , then

A = \frac{1}{2} × 20 × 40 = 10 × 40 = 400 ft²

8 0
3 years ago
Find the value of x. 3x(5+2)=16
Iteru [2.4K]

Answer:

16/21

Step-by-step explanation:

We are given the equation 3x(5 + 2) = 16.

By order of operations, let's add the two numbers in the parentheses first:

3x(5 + 2) = 16

3x(7) = 16

Now, we must multiply 3x by 7:

3x * 7 = 16

21x = 16

Divide both sides by 21:

x = 16/21

The answer is thus 16/21.

<em>~ an aesthetics lover</em>

8 0
3 years ago
Read 2 more answers
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

 = 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

6 0
3 years ago
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