Answer:
(3x^2+21x+33) / (x+5)
You can use long division:
(3x^2+21x+33)
--------------------
(x+5)
=3x+6+ 3/x+5
Step-by-step explanation:
The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
Answer:
2.600 = Exact
2.6 = Base Form
Step-by-step explanation:
?
To solve this problem we first call x = number of action figures, y = number of dolles. A system of two equations with two unknowns must be made to describe the problem. The system is the following:
(x + 1) + y = 13
1/2 * x = y.
Then solving the system we have that x = 8 and y = 4.
Since we know that the number of action figures is twice as many dolls plus one, then x = 8 + 1 = 9.
Thus,
dollos = 4
action figures = 9