We have to find the number of ways an employer send 3 employees to a job fair if she has 11 employees.
This is the problem from combination.
The formula for combination is given by
![^nC_r= \frac{n!}{r!(n-r)!}](https://tex.z-dn.net/?f=%5EnC_r%3D%20%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D)
Here, n= 11, r= 3
Therefore, total number of ways is given by
![^{11}C_3= \frac{11!}{3!(11-3)!}\\ \\ =\frac{11!}{3!8!}\\ \\ =\frac{8!\times 9 \times 10 \times 11}{3!8!}\\ \\ =\frac{9 \times 10 \times 11}{6}\\ \\ =165](https://tex.z-dn.net/?f=%5E%7B11%7DC_3%3D%20%5Cfrac%7B11%21%7D%7B3%21%2811-3%29%21%7D%5C%5C%0A%5C%5C%0A%3D%5Cfrac%7B11%21%7D%7B3%218%21%7D%5C%5C%0A%5C%5C%0A%3D%5Cfrac%7B8%21%5Ctimes%209%20%5Ctimes%2010%20%5Ctimes%2011%7D%7B3%218%21%7D%5C%5C%0A%5C%5C%0A%3D%5Cfrac%7B9%20%5Ctimes%2010%20%5Ctimes%2011%7D%7B6%7D%5C%5C%0A%5C%5C%0A%3D165)
A is the correct option.
Answer:
The value of y is y=15
Step-by-step explanation:
We have:
AB = 6y – 3, BC = 4y – 5, and CD = 7y – 18
We define the isosceles trapezoid as it has two opposites parallel, the two other opposites legs are equal and also the diagonals are equal.
Here AB = CD
6y-3 = 7y-18
Combine the like terms:
18-3 = 7y-6y
15 = y
It means the value of y is y=15....
(3,-1) just fill it in and the only one that makes sense is the first one
Answer:
6370 is the answer Hope this helps.