We assume that we are asked of the monthly contribution made by Melanie to a ROTH IRA. The give data are below:
Period = 34 years * 12 months = 408 months
Total contributions = $3,750
Solving for the monthly contribution, we have the solution below:
Monthly Contribution = Total contribution / period
Monthly contribution = $3750 / 408
Monthly contribution = $9.2
The answer is $9.2 monthly contribution.
Answer: 10 hours
Step-by-step explanation:
Given
Slow fix auto charge $28 for parts and $48 per hour of labor
We work charge $59 for parts and $44.90 per hour of labor
Suppose both works for x hours
Cost of Slow fix= 
Cost of We work= 
When these costs are the same
Answer:
20
Step-by-step explanation:
9.60 × 15= 144 9.60×5=48 15+5=20
T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
Answer:
Don't quote me on this but I believe the answer is that he is 8 years old right now if that's what you're looking for
Step-by-step explanation:
8 + 16 = 24
8 × 3 = 24
That's what I thought
