For the purpose of this, we'll set the width as x. We can then define the length as x + 22 since we know it is 22 ft longer than the width. Now we can use those along with the perimeter formula to solve for the width.

P = 2l + 2w

84 = 2(x + 22) + 2(x)

84 = 2x + 44 + 2x

84 = 4x + 44

40 = 4x

10 = x

Now since we know that the width is 10ft, we can add 22ft to it to get the length, which would be 32ft.

8 0

3 years ago

One coastal cholla cactus can house the nest of the cactus wren containing two adults and up to five young. Six cholla cacti are

saveliy_v [14]

Answer:

The maximum number of wren that could nest in the area based on the number of cholla cacti is:

42 wrens.

Step-by-step explanation:

The information provided by the text mentions that each cholla cactus can house a nest in which two adults and a maximum of five young will live (seven in total per nest), so this information can be represented as follows:

Maximum number of wrens = number of cholla cactus * 7

Since six cholla cacti are counted in the area, this value is replaced in the created equation:

Maximum number of wrens = 6 * 7
Maximum number of wrens = 42

The area could house a maximum of 42 wrens, where 12 would be adults and 30 would be young at most.

7 0

3 years ago

Which statement best describes Jim's first error￼

Which statement best describes Jim's first error