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3 years ago

Find 1/9 of 3/4 of 24

2 answers:

fomenos3 years ago

4 0

First, find 3/4 of 24. 24/4=6, 6x3= 18. Now, find 1/9 of 18. 18 divided by the denominator, 9, is 2. Since the numerator is one, our answer remains as 2. So yeah, the answer is 2.

Bingel [31]3 years ago

3 0

1/9 of 3/4 of 24 is 2

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Fill in the blank for this graph.

Agata [3.3K]

Answer:

2.22

Step-by-step explanation:

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3 years ago

Find the value of a that makes the statement true. 3^-1 ÷ 3^4 = 3^a . A = ?

Elena L [17]

A=-5 hope that helps!!

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3 years ago

Read 2 more answers

The perimeter of the isosceles ?ABC with the base BC is equal to 40 cm. Perimeter of the equilateral ?BCD is 45 cm. Find AB and

Juliette [100K]

Answer: AB = 12.5, BC = 15

Step-by-step explanation:

Perimeter of ΔBCD = BC + CD + BD. Since it is an isoceles triangle, then BC = CD = BD. So, Perimeter of ΔBCD = 3BC

3BC = 45

÷3 ÷3

BC = 15

Perimeter of ΔABC = AB + BC + AC. Since it is an isosceles triangle with BC as the base, then AB = AC. So, Perimeter of ΔABC = 2AB + BC

2AB + BC = 40

2AB + 15 = 40

-15 -15

2AB = 25

÷2 ÷2

AB = 12.5

7 0

3 years ago

AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A

Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

$\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}$ .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

$\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}$ ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

$\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}$ .....(3)

The area of triangle APM is 35m².

$\text{Area of }\triangle APM=\frac{x}{4}$

$35=\frac{x}{4}$

$x=140$

Therefore the area of triangle ABC is 140m².

Using equation (2).

$\text{Area of }\triangle APC=\frac{x}{2}$

$\text{Area of }\triangle APC=\frac{140}{2}$

$\text{Area of }\triangle APC=70$

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

$\triangle BPC=\triangle BPM+\triangle PMC$

$70=35+\triangle PMC$

$35=\triangle PMC$

Therefore the area of triangle PMC is 35m².

8 0

3 years ago

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kkurt [141]

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3 years ago