37. 6r^2
41. B
42. B
44. C
A regular polygon<span> is equilateral (it has equal sides) and equiangular (it has equal angles). To find the </span>area<span> of a regular </span>polygon<span>, you use an apothem — a segment that joins the </span>polygon's<span> center to the midpoint of any side and that is perpendicular to that side (segment HM in the following figure is an apothem).</span>
Answer:
x = 2/11
Step-by-step explanation:
1 ÷ 11/2 = x
1 · 2/11 = x (Used the opposite reciprocal and changed to multiplication. This is the same as dividing with the original fraction.)
2/11 = x
4/5 divided by 1/10 = 4/5 x 10/1 = 40/5 = 8
This is Bridge Algebra 2 stuff. Well you see that 2x+y=8 and x-1=y. To slove for y you have to slove for x first to find y. So 2x+x-1=8 ( the reason I did that is because there is a y in that equation and I placed it on that equation) now lets slove this equation for x. So 3x-1=8( I add 2x with x) 3x=9 ( I made -1 a positive one and add it to 8) x=3 ( I divided 9/3 to get 3). Now that you have slove x we will use x to slove for y. So 3-1=y, 2=y. Your answer is y=2.
