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rusak2 [61]
3 years ago
13

Dylan works out and burns 10 calories per minute swimming and 7 calories per minute biking. He wants to burn a minimum of 600 ca

lories. Due to daylight limitations, the time Dylan spends swimming must be no less than twice the time he spends biking.

Mathematics
1 answer:
Alexxandr [17]3 years ago
5 0

Answer:

The solution in the attached figure

Step-by-step explanation:

Let

x -----> the time Dylan spends swimming

y -----> the time Dylan spends biking

we know that

10x+7y \geq 600 -----> inequality A

x \geq 2y -----> inequality B

Solve the system by graphing

The solution is the shaded area

see the attached figure

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Answer: \dfrac{15}{32}

Step-by-step explanation:

Given : The number of cherry lollipop = 5

The total number of lollipop = 8

the number of lollipops other than grape =6

The probability of selecting a cherry lollipop is given by :_

\text{P(Cherry)}=\dfrac{5}{8}

The probability of selecting a lollipop other than grape is given by :_

\text{P(Other than grape)}=\dfrac{6}{8}

Since, there is replacement , then the events are independent of each other.

Now, the probability that Julie will select a cherry lollipop and then a lollipop other than grape is given by :-

\text{P(Cherry and other than grape)}=\dfrac{5}{8}\times\dfrac{6}{8}=\dfrac{15}{32}

Hence, the required probability =\dfrac{15}{32}

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3 years ago
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murzikaleks [220]
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Ben has 12 models cars in his room. These cars represent 1/2 of the model car in Ben's wholecollection. How many model car ben h
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3 years ago
UDD Question 6 10 pts Solve for x. Round to the nearest tenth (one decimal place). Just type the number, no unit of measurement.
NISA [10]

Answer:

The answer is;

54.4

Step-by-step explanation:

The given parameter are;

Triangle ΔFGH = Right triangle

The length of segment \overline {FH} = 48

The measure of ∠HFG = 28°

The measurement required = The measure of segment \overline {FG} = x

The measure of ∠FHG = 90° angle opposite hypotenuse side of a right triangle

Therefore, ∠FGH = 180° - ∠HFG - ∠FHG = 180° - 90° - 28° = 62°

∠FGH = 62°

By sine rule, we have;

\overline {FH}/(sin ∠FGH) = \overline {FG}/(sin(∠FHG)

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