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3 years ago

Answers this for me plzzz really quickly

Mathematics

2 answers:

mario62 [17]3 years ago

8 0

i am pretty sure the answer is D.

Flauer [41]3 years ago

7 0

I believe the correct answer would be D) t = -4h +21

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Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

If I plan to run 400 yards and I have completed 80%, how many yards do I have left?

Dimas [21]

Answer:

You have 80 yards left to run.

Step-by-step explanation:

To solve this problem, we first must realize that if you have completed 80% of the run, that you have 20% left (this is because 100%-80% = 20%).

Next, we must find 20% of 400 yards. We must remember that in math, the word "of" represents multiplication. We also know that 20% = 20/100 = 0.2.

To find 20% of 400 yards, we can perform the following operation:

20% * 400

0.2 * 400

Therefore, you have 80 yards left.

Hope this helps!

7 0

3 years ago

Carrie ate some of the oranges that her mother brought home from the grocery store of the oranges her mother bought 1/4 were lef

Whitepunk [10]

From the given scenario, it can be deduced that Carrie ate 3/5 of what was left of the oranges that were left. To determine the fraction that Carrie ate, we will multiply 3/5 by 1/4. This is equal to 3/20. Thus, Carrie ate approximately 3/20 of the oranges left.

3 0

3 years ago

Select the correct answer.

ella [17]

Answer:

I think its the answer is B im not sure

7 0

3 years ago

Determining whether two functions are inverses of each other.

murzikaleks [220]

F(x) = 6x + 5
g(x) = 6x - 5
f(g(x)) = 6(6x - 5) + 5 = 36x - 30 + 5 = 36x - 25
g(f(x)) = 6(6x+ 5) - 5 = 36x + 30 - 5 = 36x + 25

f and g are not inverse of each other.

4 0

3 years ago

Read 2 more answers