2 years ago

Neeeeed Helppppppp tyyyyyyyyyy

Mathematics

1 answer:

aalyn [17]2 years ago

8 0

Answer:

4a-16? i have no idea

Step-by-step explanation:

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Now work these out by changing the percentages to fractions first

svet-max [94.6K]

0.43
2
7
10
Hope this helps :-)

6 0

3 years ago

If you meet five classmates, what is the probability that three are female?

klasskru [66]

Answer:

3/5 is probability of female out of 5 classmates.

hope it helps

<h3>stay safe healthy and happy.</h3>

5 0

3 years ago

Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")