If the triangles are congruent, then their corresponding parts are also congruent.
First check to make sure the orientation of the triangles is correct. This is so we can easily compare corresponding parts.
Angle d is 180-90-52 = 38 degrees (sum of interior angles of triangle is 180 degrees), and this is the same as the angle on the triangle on the left.
Therefore the side with a length of 3 units is congruent to side c, which means side c is 3 units.
Answer: 2
Step-by-step explanation:
7-3/4-2 = 4/2 = 2
Answer:
The correct answer is: Δ ARS ≅ Δ AQT
Step-by-step explanation:
Given:
1) AR = AQ
2) ∠1 ≅ ∠3
If AR = AQ then ΔARQ is equilateral triangle, angles on the base of the equilateral triangle are the same.
3) ∠R ≅∠Q
According to this we have statement Angle-Side-Angle
Δ ARS ≅ Δ AQT
God with you!!!
Answer:
- same: 30×40 = 1200
- different: 20×50 = 1000
Step-by-step explanation:
Same: 30×40 = 1200 . . . . . 2 zeros in the factors; 2 in the product
Different: 20×50 = 1000 . . . 2 zeros in the factors; 3 in the product
__
Same: 0.3×0.4 = 0.12 . . . . no zeros in the factors; no zeros in the product
Different: 0.2×0.4 = 0.08 . . . no zeros in the factors; 1 zero in the product after the decimal point
_____
For a product, the number of zeros will be different if the combined factors of the numbers increase the number of factors of 10 beyond the sum of the factors of 10 of the numbers being multiplied.
<u>Example</u>: neither 2 nor 5 has a factor of 10, but their product does.
__
For a product that is a decimal fraction, the number of leading zeros will increase if the product of the mantissas of the numbers is less than 10. The number of trailing zeros will increase under the conditions discussed above. (0.25×0.4 = 0.100)
_____
<em>Additional comment</em>
Here, the term "mantissa" is used to refer to the portion of the number written in scientific notation that multiplies the power of 10.
Answer: 73
Step-by-step explanation:
(
3
×
−
8
)
−
(
+
4
)
+
(
2
×
−
2
)
−
5
⇒
p
(
−
2
)
=
−
24
−
4
−
4
−
5
⇒
p
(
−
2
)
=
−
37
⇒
p
(
3
)
=
3
(
3
)
3
−
(
3
)
2
+
2
(
3
)
−
5
⇒
p
(
3
)
=
(
3
×
27
)
−
9
+
6
−
5
⇒
p
(
3
)
=
81
−
9
+
6
−
5
⇒
p
(
3
)
=
73
