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svetoff [14.1K]
2 years ago
8

It is time to get the fish food ready for the marine life rescue missions. Over the last month, Penny's class has collected fish

food in a variety of boxes. In order to ship the food, you are going to help Penny and her classmates. They are going to pack the small cubes of fish food into shipping boxes that are large right rectangular prisms.
Part 2: Find the volume of the shipping box using the total number of fish food cubes.

Step 1: Find the volume of the fish food cube. Remember to include units.


MY MAIN ANSWER IS THIS?
Part 3: Find the volume of the shipping box using a volume formula. Remember to include units.

V = l × w × h = ___ × ___ ×___ = __________

Are your answers for the volume of the shipping box in Parts 2 and 3 equals? Why or why not?

Mathematics
1 answer:
professor190 [17]2 years ago
8 0

Well, you very Silly Goose This Question Is Very Easy.

First, to find the volume of the shipping box, multiply All Numbers around the object. First, you get 585/15 then you simplify and get 36 9/16.

Now to find the volume of the fish food you need to also multiply the numbers around the object. It gives you 1/64.

Lastly, no, they are not equals because they are different numbers.

So, yes, it is V= W x H x W.

Hope this helps and have a nice day!

And also May I please have Brainliest?

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UCF is a major Metropolitan University located in Orlando Florida. UCF is advertising their bachelor in Economics with the stati
Arlecino [84]

Answer:

The claim is rejected

Step-by-step explanation:

Claim: UCF is advertising their bachelor in Economics with the statistic that the starting salary of a graduate with a bachelor in economics is $ 48,500 according to Payscale (2013-13).

Null hypothesis: H_0: \mu = 48500

Alternate hypothesis :H_a : \mu \neq 48500

n = 50

Since n is more than 30 .

So we will use Z test

x=43350

Standard deviation = 15000

Z=\frac{x-\mu}{\frac{s}{\sqrt{n}}}\\Z=\frac{43350-48500}{\frac{15000}{\sqrt{50}}}\\Z=-2.42

Refer the z table

p value = 0.00776

\alpha = 0.01

p value < \alpha

So, We are failed to accept null hypothesis

Hence The claim is rejected

5 0
3 years ago
What is the value of<br> –4.00<br> –0.25<br> 1.51<br> 2.41
soldier1979 [14.2K]

For this case we must resolve the following expression:log_ {0.5} (16)

We have to:

log_ {a} (x) = \frac {log_ {b} (x)} {log_ {b} (a)}

The base change rule can be used if a and b are greater than 1 and are not equal to x.

We substitute the values in the base change formula, using b = 10

\frac {log (16)} {log (0.5)} = - 4

Answer:

-4

Option A

7 0
3 years ago
by 14 1 4 each week for a number of weeks, w . He writes the expression 20(14) 20 ( 1 4 ) w to find the amount of radioactive su
erastovalidia [21]

Answer:

1/2 ^w : decay factor after w weeks

hope this helps

Step-by-step explanation:


8 0
3 years ago
Choose all that rearrange the formula correctly.If
Sonbull [250]

Answer:

I sure hope none is an answer because none of these work!

Step-by-step explanation:

C = 59 (F - 32)

(C/59) = F - 32

F = C/59 + 32

So no :(

m = x + y + z3

y = m - x - z3

So no :((

s = r^2 - 1

r = sqrt(s+1)

So no :000

A = 12(a+b)

A = 12a + 12b

12b = A - 12a

b = A/12 - a

So no :00(((

m = x + y^2

y = sqrt (m-x)

AND no :|

5 0
2 years ago
This shape is made using three semicircles The smaller semicircle have diameters of 10cm Calculate the shaded area Take 3.142 an
CaHeK987 [17]

Answer:

The shaded area is 314.2 cm²

Step-by-step explanation:

Here we have the diameter, d₁ of the smaller semicircles as 10 cm

We note that the larger semicircle is subtended (bounded) by the two smaller semicircles;

1 shaded small semicircle and the other is blank

Therefore, the diameter, d₂ of the large semicircle = 10 + 10 = 20 cm

Also the area of the shaded figure consists of the removal of one small semicircle and the addition of the other semicircle to the area of the larger semicircle such that the area of the shaded figure is as follows

Shaded area of figure = π·d₂²/4 + π·d₁²/4 - π·d₁²/4 = π·d₂²/4 = π×20²/4 = 100×3.142 = 314.2 cm²

Shaded area = 314.2 cm².

6 0
3 years ago
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