All categories

3 years ago

Find zero of p(x) = x^3 - x/2 -7

Mathematics

1 answer:

jeka943 years ago

5 0

Answer: 73

Step-by-step explanation:

(

−

)

−

(

)

(

−

)

−

⇒

(

−

)

−

⇒

(

−

)

−

⇒

(

)

(

)

−

(

)

(

)

−

⇒

(

)

(

)

−

⇒

(

)

−

⇒

(

)

You might be interested in

75/100 in its simplest form

Oxana [17]

3/4 is the answer for your question

6 0

3 years ago

Read 2 more answers

(3x-8)° (4x-23)° fine the x

Veronika [31]

You cannot find x.

Because both phrases are to the power of 0, we know that it is essentially 1*1

So:

(3x - 8)^0 (4x - 23)^0 = 1

7 0

3 years ago

During a huge snowstrom in the white mountains last year, it snowed 300 centimeters in a week.How much did it snow in meters?

OLga [1]

3 Metres; because for each 100 centimetres there is one metre. With centi- being the prefix for 10^-2 in the metric system.

3 0

4 years ago

Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1

natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$r=\sqrt{(-5-(-2))^2+(3-1)^2}$

$r=\sqrt{(-5+2)^2+(2)^2}$

$r=\sqrt{(-3)^2+(2)^2}$

On further simplification, we get

$r=\sqrt{9+4}$

$r=\sqrt{13}$

The standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and $r=\sqrt{13}$ .

$(x-(-2))^2+(y-1)^2=(\sqrt{13})^2$

$(x+2)^2+(y-1)^2=13$

Therefore, the equation of the circle is $(x+2)^2+(y-1)^2=13$ .

8 0

3 years ago

If 0 = 6n -36 what is the value of n -5

juin [17]

0=6n- 36

6n-36

6 x-5-36

35-36

n=-1
I hope this help

8 0

3 years ago

Find zero of p(x) = x^3 - x/2 -7​

Find zero of p(x) = x^3 - x/2 -7