(x-h)^2=4p(y-k)
vertex is (h,k)
p is the distance from focus to vertex and distance from vertex to directix (vertex is in middle of directix and focus)
if p is positive, the parabola opens up and the focus is above the directix
if p is negative, the parabola opens down and the focus is below the directix
we see the directix is over the focus (1>-1) so the parabola opens down and p is negative
distance from (5,-1) to y=1 is 2 units
2/2=1
p=-1 since p is negative
1 up from (5,-1) is (5,0)
veretx is (5,0)
(x-5)^2=4(-1)(y-0)
(x-5)^2=-4y is the equation
Answer:
A
Step-by-step explanation:
I may be wrong,If i am i apoligize fr the inconvenience!!
If not, Your very welcome.
Answer:
D pi/4, 3pi/4
Step-by-step explanation:
Differentiate the function then equal it to zero and solve for the interval (see attached workings)
Answer:
{-0.36, 8.36) to the nearest hundredth.
Step-by-step explanation:
x^2 - 8x = 3
(x - 4)^2 - 16 = 3
(x - 4)^2 = 19
Taking square roots:
x - 4 = +/- √19
x = 4 +/- √19
x = {-0.36, 8.36} to nearest 1/100.
Not sure!!!!!;( next time put a pic
