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Zanzabum
4 years ago
6

SOMEONE PLEASE HELP ME ASAP PLEASE!!​

Mathematics
1 answer:
kogti [31]4 years ago
8 0
Y = 4/5 + (-2)
Explanation: try this out yourself to see if it works
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The endpoints of one diagonal of a rhombus are (0, -8) and (8, -4). If the coordinates of the 3rd vertex are (1, 0), what are th
xeze [42]
The answer is (-7, -12).

Attached is the graph to show the answer.

4 0
3 years ago
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Which product is negative?
xxTIMURxx [149]
Negative times a Negative = Positive
Positive times a Positive = Positive
Negative times a Positive = Negative
Positive times a Negative = Negative

Option A:

Negative * Positive * Negative * Positive

Negative * Negative * Positive

Positive * Positive

Positive

Option B:

Anything times 0 is 0, this is incorrect.

Option C:

Negative * Negative * Negative * Negative

Positive * Negative * Negative

Negative * Negative

Positive

Option D:

Negative * Positive * Negative * Negative

Negative * Negative * Negative

Positive * Negative

Negative

Therefore your answer is D.
4 0
3 years ago
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What are the two ways you can find the distance between points (X1,Y1) and (x2,y2) in the coordinate
igomit [66]

The first (and most typical) way to find distance of two points is by using the distance formula.

distance=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2  }

One alternative is the Manhattan metric, also called the taxicab metric. This option is much more complicated, and rarely used in high school math. d(x,y)=∑i|xi-yi|

4 0
4 years ago
Bananas are $0.59/pound, how much will 25 bananas cost?
yKpoI14uk [10]
The answer would be $14.75. You would have to do .59 times 25 bananas and you would would get $14.75.
7 0
4 years ago
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What are the solutions of the equation (x – 3)2 + 2(x – 3) -8 = 0? Use u substitution to solve.
Andrej [43]

Answer:

x = -1 and x = 5

Step-by-step explanation:

<em>What are the solutions of the equation (x – 3)² + 2(x – 3) -8 = 0? Use u substitution to solve.</em>

<em />

(x – 3)² + 2(x – 3) -8 = 0   -------------------------------------------------------(1)

To solve this problem, we will follow the steps below;

let u = x-3

we will replace x-3 by u in the given equation:

(x – 3)² + 2(x – 3) -8 = 0  

u² + 2u -8 = 0  ----------------------------------------------------------- --------------(2)

We will now solve the above quadratic equation

find two numbers such that its product gives -8 and its sum gives 2

The two numbers are 4 and -2

That is; 4×-2 = -8    and 4+(-2) = 2

we will replace 2u by (4u -2u)  in equation (2)

u² + 2u -8 = 0

u² + 4u - 2u -8 = 0

u(u+4) -2(u+4) = 0

(u+4)(u-2) = 0

Either  u + 4 = 0

            u = -4

or

u-2 = 0

u = 2

Either u = -4    or u = 2

But  u = x-3

x = u +3

when u = -4

x = u + 3

x = -4 + 3

x=-1

when u = 2

x = u + 3

x = 2 + 3

x=5

Therefore, x = -1  and  x =5

x

6 0
3 years ago
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