Answer:
![\frac{7(a-1)}{(a+2)(a-5)}](https://tex.z-dn.net/?f=%5Cfrac%7B7%28a-1%29%7D%7B%28a%2B2%29%28a-5%29%7D)
Step-by-step explanation:
To solve this operation we need to find the common multiple of both denominators and solve for a.
![\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7Ba%2B2%7D%20%2B%20%5Cfrac%7B4%7D%7Ba-5%7D%20%3D%5Cfrac%7B3%28a-5%29%2B4%28a%2B2%29%7D%7B%28a%2B2%29%28a-5%29%7D%20%3D%5Cfrac%7B3a-15%2B4a%2B8%7D%7B%28a%2B2%29%28a-5%29%7D%20%3D%5Cfrac%7B7a-7%7D%7B%28a%2B2%29%28a-5%29%7D%20%3D%5Cfrac%7B7%28a-1%29%7D%7B%28a%2B2%29%28a-5%29%7D)
Thus, the solution is 7(a -1) / (a+2)(a-5)
The amount spent on each tube is $18.5
The total amount spent to rent 15 tubes by the group is $277.50.
Since they did not specify in the question the types of tubes they rented, we cannot determine each types of tubes that the group rented but we can determine the amount spent on each tube provided that they are all the same types.
∴
if 15 tubes = $277.50
1 tube = $x
By cross multiplying:
![\mathbf {\$(x) = \dfrac{ \$277.50 \times 1 \ tube }{15 \ tube}}](https://tex.z-dn.net/?f=%5Cmathbf%20%7B%5C%24%28x%29%20%3D%20%5Cdfrac%7B%20%5C%24277.50%20%5Ctimes%201%20%5C%20tube%20%7D%7B15%20%5C%20tube%7D%7D)
![\mathbf {(x) = \$18.5}](https://tex.z-dn.net/?f=%5Cmathbf%20%7B%28x%29%20%3D%20%5C%2418.5%7D)
Therefore, we can conclude that the amount spent on each tube is $18.5
Learn more about arithmetic operations here:
brainly.com/question/15385899?referrer=searchResults
Answer:
Step-by-step explanation:
by moving the decimal 2 times to the right
One- twelfth for the first tiny line and the two-twelfth and so on until u reach 1
take 16+5=21. 29-21=8 so answer is 8