10w^7 is the answer I’m pretty sure
By the pythagorean theorem a^2 + b^2 = c^2 so if we do 8^2 + 6^2 it is 100
I am absolutely sure that the task <span> b = 3, then 3x + y = 1 and bx - y = 3 is NOT parallel, which means that the statement represented above is FALSE.
To make sure you can check it using : </span>
Hope now it's obvious. Regards!
Answer:
see explanation
Step-by-step explanation:
Using the Addition/ Subtraction formulae for cosine
Consider the left side
cos(x - y) - cos(x + y)
= cosxcosy + sinxsiny - (cosxcosy - sinxsiny) ← distribute
= cosxcosy + sinxsiny - cosxcosy + sinxsiny ← collect like terms
= 2sinxsiny = right side ⇒ proven
Because the cosine and sine must be negative when evaluated in theta, the angle lies on the third quadrant.
<h3>
In which quadrant is the endpoint of the segment that defines the angle?</h3>
We know that if:
- cos(θ) > 0, then we are on the first or fourth quadrant
- sin(θ) > 0, then we are on first or second quadrant.
Here we know that:
sec(θ) < 0
And we know that:
sec(θ) = 1/cos(θ)
Then we have cos(θ) < 0
We also have that:
sec(θ)*csc(θ) > 0
Because sec(θ) < 0, we must have that csc(θ) < 0.
Remember: csc(θ) = 1/sen(θ)
Then sen(θ) < 0.
Then we have the two conditions:
sen(θ) < 0
cos(θ) < 0
- The cosine is negative on the third and second quadrants.
- The sine is negative on the third and fourth quadrants.
The only quadrant where both are negative is the third quadrant, so that is the correct option.
If you want to learn more about trigonometric functions:
brainly.com/question/8120556
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