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2 years ago

15

Amelia recorded the average rainfall amount, in inches, for two cities over the course of a few months.

2 answers:

Ann [662]2 years ago

6 0

City a: 5+4+3+5+5+4+2=28 divided by 7=4. city b:3+6+7+3+8+3=30 divided by 6=5.
B)City a: 4, city b: 1.5.
that is all i can do.

kondaur [170]2 years ago

5 0

A.) City A = 4 (2+3+4+4+5+5+5=28,28/7=4) City B = 5 (3+3+3+6+7+8=30,30/6=5)
B.) City A = 4 (2,3,4,4,5,5,5) City B = 4.5 (3,3,3,6,7,8)
C.) City A = 5 City B= 3
D.) City A = 3 City B = 5

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40 is a rational number.

Sauron [17]

Answer: if its a true or false question then yes 40 is a rational number

Step-by-step explanation:

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3 years ago

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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.

Irina18 [472]

Answer:

<u>TO FIND :-</u>

Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$
$\tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}$

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

$=> \sin 16 = \frac{7}{x}$

$=> \frac{7}{x} = 0.27563......$

$=> x = \frac{7}{0.27563....} = 25.39568.....$ ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

$=> \sin 29 = \frac{6}{x}$

$=> \frac{6}{x} = 0.48480......$

$=> x = \frac{6}{0.48480....} = 12.37599.....$ ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

$=> \sin 30 = \frac{x}{11}$

$=> \frac{x}{11} = 0.5$

$=> x = 0.5 \times 11 = 5.5$

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

$=> \cos 43 = \frac{x}{12}$

$=> \frac{x}{12} = 0.73135......$

$=> x = 12 \times 0.73135.... = 8.77624....$ ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

$=> \cos 55 = \frac{x}{6}$

$=> \frac{x}{6} = 0.57357......$

$=> x = 6 \times 0.57357.... = 3.44145....$ ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

$=> \cos 73 = \frac{8}{x}$

$=> \frac{8}{x} = 0.29237......$

$=> x = \frac{8}{0.29237.....} = 27.36242.....$ ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

$=> \tan 69 = \frac{12}{x}$

$=> \frac{12}{x} = 2.60508......$

$=> x = \frac{12}{2.60508....} = 4.60636....$ ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

$=> \tan 20 = \frac{11}{x}$

$=> \frac{11}{x} = 0.36397......$

$=> x = \frac{11}{0.36397....} =30.22225....$ ≈ 30.2

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2 years ago

Can someone help? 25 points

denpristay [2]

Answer:

the answer is 157

Step-by-step explanation:

i had a test with the same question, i promise its right :)

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3 years ago

Fraction equivalent to 3/12

Rufina [12.5K]

Two of them are 1/4 and 2/8! Hope this helps:)

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3 years ago

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Given: cos α = 4/5, sin β= 4/5, and α and β are both in quadrant 1. find sin (α+β)

mezya [45]

We have the formula (sin x)^2 + (cos x)^2 = 1;
Then, sin α = $\sqrt{1- ( \frac{4}{5}) ^{2} } = \frac{3}{5} ;$
cos β = $\sqrt{1- ( \frac{4}{5}) ^{2} } = \frac{3}{5} ;$
We apply the formula sin ( α + β ) = sin α x cos β + sin β x cos α = (3/5)x(4/5) + (4/5)x(3/5) = 12/25 + 12/25 = 24/25;

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3 years ago