Hi
The volume is 58.1
The moler mass is 10.8
Molar mass details
10.81B (1*10.81)
Hope this helps
Would the answer be d wouldn't it
D. It is the heat required to change a gram of substance from a liquid to a gas.
Explanation:
The heat of vaporization is the heat required to change a gram of substance from a liquid to a gas.
- It is also known as the enthalpy of vaporization.
- The heat of vaporization is the quantity of heat needed to change one gram of a substance from liquid to gas.
- This heat of vaporization is dependent on the pressure conditions the process is taking place.
- Different liquids have their heat of vaporization.
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Heat of vaporization brainly.com/question/9529654
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Same as a normal human would have. 24 ribs or 12 pairs of ribs in each side. There is no discrepancy in the number of ribs whether the human is old or young; male or female (contrary to the unpopular belief that a male has an extra pair of ribs).
1 mole of steam (H2O) = 18g
Heat evolved = MCФ where m is the mass and c s specific heat capacity while Ф is change in temperature. Latent heat of fusion is 334 kj/kg while latent heat of vaporization is 2260 kj/kg and specific heat of water is 4.2 j/g/c
= 18 ×2.01 × (135-100) = 1266.3 J
0.018 × 334000 = 6012 J (change of state from gas (steam) to liquid (water)
18 × 4.186× (100 -0) = 7534.8 J
0.018 × 2260000 = 40680 J (change of state from liquid to solid ice)
18 × 2.09 × (0--45) = 1692.9 J
The total heat evolved is therefore 57186 J or 57.186 kJ