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Ostrovityanka [42]
3 years ago
15

Plzz giving brainlist to first answer!Plss fill in the blanks!!ASAP.Modeling Our Solar System

Chemistry
1 answer:
Gwar [14]3 years ago
3 0

Answer:

The planets follow these orbit  paths as they travel around the Sun. The Sun’s gravity  

makes the planets move in this way. It pulls on the planets, keeping them in motion in their orbit.

Modeling is a way to see ideas or have a  particular idea or

concept.

 Models do have some lines .

 Often a model is made with certain things.

 A model of the solar system may contain all of the planets and the Sun, but it may not include the planets’

individual moons or every planit  and rock in the solar system.

Explanation: if you think about it and and look at pics it is easy

hope this helps

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1.- Ilumina de amarillo los verbos en pretérito y de verde los verbos en copretérito.
ivanzaharov [21]

Answer:

Pretérito (Pretérito perfecto):

<em>estiró, sudó, peleó, compartí</em>

Copretérito (Pretérito imperfecto):

<em>saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian</em>

Explanation:

Los verbos en pretérito, también llamado pretérito perfecto, son los siguientes:

<em>estiró, sudó, peleó, compartí</em>

Como se aprecia, los verbos conjugados en pretérito perfecto terminan la última sílaba en vocal con acento, es decir, <em>-á</em>, <em>-é</em>, <em>-í</em> u <em>-ó</em>.

Los verbos en copretérito, también llamado pretérito imperfecto, son los siguientes:

<em>saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian</em>

Como se aprecia, los verbos conjugados en pretérito imperfecto terminan la última sílaba en <em>-ía</em>, <em>ías</em>, <em>-ían</em>, <em>-aba</em>, <em>-abas</em> o <em>-aban</em>.  

3 0
3 years ago
PLZ HELP PLZ PLZ ILL MARK AS BRAINLIESTT!!!!
LuckyWell [14K]

Q.1-

Given,

mass - 10grams

volume - 24 cm³

density = mass/volume

density = 10/24

density = 0.416 g/cm³

Q.2-

Given,

mass - 700grams

volume - 1100cm³

density = mass/volume

density = 700/1100

density = 0.6363 g/cm³

5 0
3 years ago
Grade 8 Science
ira [324]
Materials<span> and their </span>properties<span>: </span>compounds like<span> sodium chloride - an interactive educational resource for 11 to 14 year olds. ... Elements are substances (</span>like<span> hydrogen and oxygen) that can't be split into simpler substances. ... For </span>each<span> statement, decide whether it describes a mixture or a </span>compound<span> and check the box.</span>
8 0
3 years ago
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of sodium sulfa
notka56 [123]

Answer:

27%

Explanation:

Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

2NaOH+H_2SO_4-->Na_2SO_4+2H_2O

Now, to compute the percent yield, we must first establish the limiting reagent to subsequently determine the theoretical yield of sodium sulfate because the real (1.92g) is already given, thus, we consider the following procedure:

n_{NaOH}=7.8gNaOH*\frac{1molNaOH}{40gNaOH}=0.2molNaOH\\n_{H_2SO_4}=4.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.050molH_2SO_4\\

- The moles of sodium hydroxide that completely react with 0.05 moles of sulfuric acid are:

0.2molNaOH*\frac{1molH_2SO_4}{2molNaOH}=0.098molH_2SO_4

As this number is higher than the previously computed 0.05 moles of available sulfuric acid, one states that the sulfuric acid is the limiting reagent. Now, the theoretical grams of sodium sulfate are found via:

0.05molH_2SO_4*\frac{1molNa_2SO_4}{1mol H_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4} =7.1gNa_2SO_4

Finally, the percent yield turns out into:

Y=\frac{1.92g}{7.1g} *100

Y=27.0%

Best regards.

6 0
3 years ago
Which element exhibits a crystalline<br> structure at STP?<br> 1)F<br> 2)CI<br> 3)Br<br> 4) I
umka21 [38]
It would be F only because I wouldn’t make sense CI doesn’t exhibit crystalline neither does BR so F
6 0
3 years ago
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