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3 years ago

Eva invests $6400 in a new savings account which earns 3.4 % annual interest, compounded continuously. What

Mathematics

1 answer:

cupoosta [38]3 years ago

7 0

Answer:

$7821.74

Step-by-step explanation:

Eva invests $6400 in a new savings account which earns 3.4% annual interest, compounded continuously.

We have to find the value of her investment after 6 years,

Now, using the formula for the compound interest we can get the value of her investment.

So, it will be $V = 6400 (1 + \frac{3.4}{100} )^{6} = 7821.74$ Dollars (Approximate)

{Rounded to the nearest cent} (Answer)

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Find the perimeter of a square that is 3inches on a side. 7 inches 15 inches 12 inches 30 inches

In-s [12.5K]

Answer:

12 inches

Step-by-step explanation:

A square has 4 sides with the same length.

The perimeter of a square is the 4 times the length of one side.

perimeter = 4s

perimeter = 4 * 3 inches

perimeter = 12 inches

4 0

3 years ago

Read 2 more answers

Can anybody help me please

MatroZZZ [7]

Answer:

○ 4⁄6, -4⁄6

Step-by-step explanation:

Take the square root of both the denominator and numerator, and you will get the above two answers.

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3 years ago

Solve for x. (17x - 23) (&r - 4)* -(3x + 17)

Finger [1]

Answer:

17rx2−23rx−71x+75

Step-by-step explanation:

(17x−23)(xr−4)−(3x+17)

=(17x−23)(xr−4)+−1(3x+17)

=(17x−23)(xr−4)+−1(3x)+(−1)(17)

=(17x−23)(xr−4)+−3x+−17

=(17x)(xr)+(17x)(−4)+(−23)(xr)+(−23)(−4)+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=(17rx2)+(−23rx)+(−68x+−3x)+(92+−17)

=17rx2+−23rx+−71x+75

6 0

3 years ago

A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the

Naya [18.7K]

Answer:

The area is growing at a rate of $\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

Step-by-step explanation:

Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.

We identify that the info given on the increasing rate of the circle's radius is 3 $\frac{cm}{min}$ and we identify such as the following differential rate:

$\frac{dr}{dt} = 3\,\frac{cm}{min}$

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find $\frac{dA}{dt}$ .

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

$A=\pi\,r^2$

We now apply the derivative operator with respect to time ( $\frac{d}{dt}$ ) to this equation, and use chain rule as we find the quadratic form of the radius:

$\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}$

Now we replace the known values of the rate at which the radius is growing ( $\frac{dr}{dt} = 3\,\frac{cm}{min}$ ), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

$\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\$