Answer:
A sample size greater than 30
Step-by-step explanation: The central limit theorem proffers the conditions necessary to obtain a normal or bell shaped distribution. It defines normal distribution in terms of mean, standard deviation and sample size. The sample size is a very important factor in determining the shape of a distribution.
Thus with a population having mean and standard deviation stated, in other to make use of or assume normal distribution, the sample size must be large. According tho the central limit theorem, a size of greater than 30 is deemed to be large enough. As the Same size increases, the sample mean converges to the value of the population mean.
RQ × RP = RS × RT
9 × ( 9 + 13 ) = 11 × RT
9 × 22 = 11 × RT
Divide sides by 11
9 × 22 / 11 = 11 × RT / 11
Simplification
9 × 2 = RT
RT = 18
To find the mean, you add up the numbers and divide by
how many numbers there are.
So if the mean of 'A' and 'B' is 40, then A + B = 80 .
And if the mean of 'B' and 'C' is 35 then B + C = 70.
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You said that (A + B) + C = 100 .
From something else that you said, I noticed that A + B = 80 .
So I can write (80) + C = 100
Subtract 80 from each side: C = 20
==========================================
I also noticed, from what you said, that B + C = 70 .
So I can write B + 20 = 70
Subtract 20 from each side: B = 50
==========================================
Now I know that C = 20 and B = 50.
Finally, you said that A + B + C = 100 ,
So I can write A + 50 + 20 = 100
Combine like terms on the left: A + 70 = 100
Subtract 70 from each side: A = 30
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<em> A = 30</em>
<em> B = 50</em>
<em> C = 20</em>
Answer:
30%
Step-by-step explanation:
The local zoo contained 40 exhibits in total. It contained 12 reptile exhibits.
The percentage of the zoo's exhibits that feature reptiles is gotten by dividing the number of reptile exhibits by the total exhibits and then, multiplying by 100:
=> (12 / 40) * 100
= (3 / 10) * 100 = 300 / 10
= 30%
30% of the zoo's exhibits feature reptiles.
Answer:
8x - 20
Step-by-step explanation:
6(2x - 3) - 2(2x + 1)
Distribute
6(2x) -6( 3) - 2(2x) -2( 1)
12x -18 -4x -2
Combine like terms
12x -4x -18 -2
8x-20
