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algol13
3 years ago
5

Rob is making a tent out of canvas in the shape of a square pyramid. Each side of the square base is 6 feet long, and the height

is 6.3 feet. If rob filled the tent with balloons, which measurement BEST describes the amount of balloons in the tent? (round to nearest whole number) A) 76 ft2 B) 120 ft2 C) 76 ft3 D) 120 ft3
Mathematics
2 answers:
Elena L [17]3 years ago
6 0

The amount of balloons in the tent is 125.075 feet cube. From the given options, approximately, option D is correct

<u>Solution:</u>

Given, Rob is making a tent out of canvas in the shape of a square pyramid.  Each side of the square base is 6 feet long, and the height is 6.3 feet.  

Rob filled the tent with balloons,  

We have to find which measurement BEST describes the amount of balloons in the tent?  

As tent if filled with balloons the amount of balloons equals with volume of tent.

<em><u>Volume of tent is given as:</u></em>

\text { volume of tent }=a^{2}+2 a \sqrt{\frac{a^{2}}{4}+h^{2}}

where "a" is side length and "h" is height.

\begin{array}{l}{\text { Then, Volume }=6.3^{2}+2(6.3) \sqrt{\frac{6.3^{2}}{4}+6^{2}}} \\\\ {=39.69+12.6 \sqrt{9.925+36}} \\\\ {=39.69+12.6 \times 6.7766=39.69+85.385} \\\\ {=125.075 \mathrm{ft}^{3}}\end{array}

Hence, from the given options, approximately, option D is correct.  

amid [387]3 years ago
5 0

Answer: 12 ft2

Step-by-step explanation:

120 ft2

Surface area measures the outside surface in square units.

SA =  

1

2

lp + B =  

1

2

(7)(24) + 62 = 120

l = slant height, p = base perimeter, B = base area

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107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
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107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
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107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0



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