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We have one of those equations already solved for y, so let's sub that one into the other one and solve the equation in terms of x only: 
. We will simplify that and at the same time bring the 6 over by subtraction to get a polynomial set to equal 0 that we can factor. 
. We will factor that to get (x-3)(x+1) for x values of x = 3 and x = -1. a above is the choice that has the x values we need, -1 and 3.