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babymother [125]
3 years ago
9

Evaluate and simplify (-2)^4/(3^2+2^2)^2

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0

Answer: 16/169

Step-by-step explanation:

1. Evaluate the power

  • 16/(x^2+2^2)^2
  • 16/(9+2^2)^2
  • 16/(9+4)^2

2. Add the numbers

  • 16/13^2

3. Evaluate the power

  • 16/169

4. Solution, 16/169

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3 years ago
Help middle school question!!!
Sav [38]

Answer:

<em>The shaded region has an area of 1400 square units</em>

Step-by-step explanation:

<u>Area of Compound Shapes</u>

We are given a shape and it's required to calculate its area. The shape can be divided into three rectangles as shown in the figure attached below.

The lengths of these rectangles are x, y, and z.

The value of x can be calculated as:

x = 60 - 15 - 10 = 35

Similarly:

y = 60 - 15 = 45

z = y = 45

The first rectangle has dimensions of x by 10, thus its area is:

A1 = 35*10 = 350

The second rectangle has dimensions of 60 by 10:

A2 = 60*10 = 600

The third rectangle has dimensions y by 10:

A3 = 55*10 = 450

The shaded area is:

A = 350 + 600 + 450 = 1400

The shaded region has an area of 1400 square units

8 0
2 years ago
Read 2 more answers
Make a ten or a hundred to add mentally 339+123
lianna [129]
9+3=12
30+20=50
300+100=400
Then add.
12+50+400=462
<span>So 339+123=462</span>
5 0
2 years ago
Can someone help me find the domain of this function please ?
ratelena [41]

Answer: It is A=-1<x<-6 is the domain

4 0
3 years ago
X+y+z =4
cestrela7 [59]
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian : 
Akar-akar persamaan lama :  x1 dan x2
                                             
Akar-akar persamaan baru :  xA dan xB
                                             xA = 2x1 - 1
                                             xB = 2x2 - 1
                                             xA + xB  = (2x1 - 1) + (2x2 - 1)
                                                           = 2 (x1 + x2) - 2
                                                           = 2 () - 2
                                                           = 3 - 2
                                              xA + xB = 1
    
                                              xA . xB = (2x1 - 1) (2x2 - 1)
                                                          = 4 x1.x2 - 2(x1 + x2) + 1
                                                          = 4.(-) - 2() + 1
                                                          = -2 - 3 + 1
                                              xA . xB = -4
    
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
                                              x² - x - 4 = 0

</span></span>
4 0
3 years ago
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