All categories

3 years ago

Use the graph of y= e^x to evaluate e^1.7 to four decimal places

Mathematics

1 answer:

bagirrra123 [75]3 years ago

7 0

answer is attached below

You might be interested in

Dylan read 210 pages of a book in 5 days. He read 37 pages each day for the first 3 days He read y pages the fourth day. Which e

Setler79 [48]

6794638573463736373u434737463

8 0

2 years ago

Read 2 more answers

5.8 cm converted into cm

agasfer [191]

Answer:

but it is already in cm

5.8 cm is 5.8 cm but if you want mm

5.8 cm is 58 mm

Step-by-step explanation:

8 0

3 years ago

Plz help!!! I have a bad grade as it is and i don't want to drop it

Travka [436]

$Answer: \\ The\: area\: of\: the\: shaded\: region\\ =Area\: of\: square - Area\: of\: circle\\ = {28}^{2} - 3.14 \times {14}^{2} = 784 - 615.44 = 168.56 \: {in}^{2}$

5 0

2 years ago

What is the whole number to make statement true ? ÷7 >800

slava [35]

Any whole number above 5600, not counting 5600.

the number 5600 would make them equal, but it needs to be greater than. so any whole number above 5600 would make the statement true:

800(7)= 5600
5600 / 7 = 800
so,
5601 / 7 > 800 is a true statement

again, any whole number above 5600 is a correct answer, there are an infinite amount of solutions

4 0

2 years ago

Read 2 more answers

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is

anastassius [24]

Answer:

The rate of change of temperature is 1.29 degree Celsius per second.

Step-by-step explanation:

We are given the following information in the question:

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius where x and y are measured in centimeters.

$x = \sqrt{2+t}\\\\y = 5 + \displaystyle\frac{1}{14}t$

$T_x(4,6) = 8, T_y(4,6) = 4$

We have to find the rate at which the temperature is rising on the bug's path after 14 seconds.

At t = 14 seconds, we have,

$x = \sqrt{2+14} = 4\\\\y = 5 + \displaystyle\frac{1}{14}(14) = 5+1 = 6$

To find rate of change of temperature, we differentiate,

$\displaystyle\frac{dT}{dt} = \frac{dT}{dx}\frac{dx}{dt} + \frac{dT}{dy}\frac{dy}{dt}\\\\\displaystyle\frac{dT}{dt} = T_x(x,y)(\frac{1}{2\sqrt{2+t}}) + T_y(x,y)\frac{1}{14}\\\\At~ t = 14, x = 4, y = 6\\\\\frac{dT}{dt} = T_x(4,6)(\frac{1}{2\sqrt{2+t}}) + T_y(4,6)\frac{1}{14}\\\\\frac{dT}{dt} = 8\times \frac{1}{8} +4\times \frac{1}{14} = 1 + 0.2857 = 1.2857$

Thus, the rate of change of temperature is 1.29 degree Celsius per second.

7 0

2 years ago