Look at the link below I filled in the answers for you. :)
Option 3:
m∠ABC = 66°
Solution:
Given
and ABH is a transversal line.
m∠FAB = 48° and m∠ECB = 18°
m∠ECB = m∠HCB = 18°
<u>Property of parallel lines:
</u>
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠FAB = m∠BHC
48° = m∠BHC
m∠BHC = 48°
<u>Exterior angle of a triangle theorem:
</u>
<em>An exterior angle of a triangle is equal to the sum of the opposite interior angles.</em>
m∠ABC = m∠BHC + m∠HCB
m∠ABC = 48° + 18°
m∠ABC = 66°
Option 3 is the correct answer.
9514 1404 393
Answer:
-4
Step-by-step explanation:
The points at the ends of the interval are ...
(3, f(3)) = (3, 8)
(6, f(6)) = (6, -4)
The slope is given by the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (-4 -8)/(6 -3) = -12/3 = -4
The average rate of change is -4.