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Brut [27]
3 years ago
5

What is k?

Mathematics
1 answer:
andrezito [222]3 years ago
4 0
Solve for k by simplifying both sides of the equation, then isolating the variable.
k= 23/3
simplified= 7 2/3
D. is your answer
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A bird flies from the bottom of a canyon that is 71 4/5 feet below sea level to a nest that is 875 7/10 feet above sea level. Wh
Rainbow [258]

The difference in elevation between the bottom of the canyon and the​ bird's nest is 947 1/2 feet

<h3>What is the difference in elevation between the bottom of the canyon and the​ bird's nest?</h3>

The given parameters are:

Nest = 71 4/5 feet above the seal level

Bottom of canyon = 875 7/10 below sea level

Below sea level means negative

So, we have:

Nest = 71 4/5 feet

Bottom of canyon = -875 7/10

The difference in elevation between the bottom of the canyon and the​ bird's nest is calculated as

Difference = |Nest - Bottom of canyon|

This gives

Difference = |71 4/5 - (-875 7/10)|

Evaluate the difference

Difference = |947 1/2|

Remove the absolute bracket

Difference = 947 1/2

Hence, the difference in elevation between the bottom of the canyon and the​ bird's nest is 947 1/2 feet

Read more about depth at:

brainly.com/question/17147411

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8 0
1 year ago
a local hamburger shop sold a combined total of 613 hamburgers and cheeseburger on Friday. there were 63 more cheeseburger sold
kondaur [170]

Answer:

275 hamburgers was sold on Friday

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2 years ago
Write numbers to make each line have the same sum
wlad13 [49]

Answer:

There is nothing here?

Step-by-step explanation:

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2 years ago
Can someone help me with question 9
Troyanec [42]

Please refer the pictures below-

Hence the area of the road is 9600m2

8 0
3 years ago
Assume that a simple random sample has been selected from a normally distributed population. State the hypotheses, find the test
BaLLatris [955]

Solution

Hypotheses:

- The population mean is 132. In order to test the claim that the mean is 132, we should check for if the mean is not 132.

- Thus, the Hypotheses are:

\begin{gathered} H_0:\mu=132 \\ H_1:\mu\ne132 \end{gathered}

Test statistic:

- The test statistic has to be a t-statistic because the sample size (n) is less than 30.

- The formula for finding the t-statistic is:

\begin{gathered} t=\frac{\bar{X}-\mu}{\frac{s}{\sqrt{n}}} \\  \\ where, \\ \bar{X}=\text{ Sample mean} \\ \mu=\text{ Population mean} \\ s=\text{ Standard deviation} \\ n=\text{ Sample size} \end{gathered}

- Applying the formula, we have:

\begin{gathered} t=\frac{137-132}{\frac{14.2}{\sqrt{20}}} \\  \\ t=\frac{5}{3.1752} \\  \\ t\approx1.5747 \end{gathered}

Critical value:

- The critical value t-critical, is gotten by reading off the t-distribution table.

- For this, we need the degrees of freedom (df) which is gotten by the formula:

\begin{gathered} df=n-1 \\ df=20-1=19 \end{gathered}

- And then we also use the significance level of 0.1 and the fact that it is a two-tailed test to trace out the t-critical. (Note: significance level of 0.1 implies 10% significance level)

- This is done below:

- The critical value is 1.729

P-value:

- To find the p-value, we simply check the table for where the t-statistic falls.

- The t-statistic given is 1.5747. We simply check which values this falls between in the t-distribution table. It falls between 1.328 and 1.729. We can simply choose a value between 0.1 and 0.05 and multiply the result by 2 since it is a two-tailed test.

- However, we can also use a t-distribution calculator, we have:

- Thus, the p-value is 0.13183

Final Conclusion:

- The p-value is 0.13183, and comparing this to the significance level of 0.1, we can see that 0.13183 is outside the rejection region.

- Thus, the result is not significant and we fail to reject the null hypothesis

7 0
1 year ago
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