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4 years ago

Question 1 of 10

Mathematics

1 answer:

guapka [62]4 years ago

4 0

Answer:

$\large\boxed{y+7=-3(x-5)}$

Step-by-step explanation:

$\text{The point-slope form of an equation of a line:}\\\\y-y_1=m(x-x_1)\\\\m-slope\\(x_1,\ y_2)-point\\\\\text{We have}\ m=-3\ \text{and}\ (5,\ -7).\\\text{Substitute:}\\\\y-(-7)=-3(x-5)\\y+7=-3(x-5)$

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How would you describe mathematics?

Umnica [9.8K]

Answer:

Mathematics is the science that deals with the logic of shape, quantity and arrangement.

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3 years ago

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Find the equation for the line containing the points (-2,-5) and (6,3)

kow [346]

Answer:

y = x - 3

Step-by-step explanation:

Do rise/run to find the slope

8/8 = 1

y = x + b

Plug in a point to find the y-intercept

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4 years ago

Rewrite the product as a sum or difference.<br><br> 20cos(36t) cos(6t)

tiny-mole [99]

The applicable identity is ...

... cos(a)cos(b) = (1/2)(cos(a+b) +cos(a-b))

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... 20cos(36t)cos(6t) = 20·(1/2)(cos(36t+6t) + cos(36t-6t))

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4 years ago

QUESTION 1 - 1 POINT

guajiro [1.7K]

Answer + Step-by-step explanation:

the inequality by finding the boundary line, then shading the appropriate area.

y > − 5/2x − 5

(anything in shaded region)

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2 years ago

Please answer a question the images.

Lyrx [107]

The distribution of the animals in the coral reef is an illustration of probability

<h3>The most likely animal</h3>

The distribution of the animals is given as:

Blue fish = 3

Yellow fish = 7

Sea turtle = 1

Eels = 3

The animal with the highest frequency is the most likely animal.

Hence, the Yellow fish is the most likely animal.

<h3>Which is more likely?</h3>

From the question, we have:

Blue fish = 3

Eels = 3

Both animals have the same frequency.

This means that Riley has equal chance of seeing a blue fish and an eel.

<h3>The probability of seeing an animal with fins</h3>

The animal with fins are:

Blue fish = 3

Yellow fish = 7

So, the probability is:

$p = \frac{3 + 7}{3 + 7 + 1 + 3}$

$p = \frac{10}{14}$

Simplify

$p = \frac 57$

Hence, the probability of seeing an animal with fins is 5/7

<h3>The least likely animal</h3>

The animal with the least frequency is:

Sea turtle = 1

So, the likelihood is:

$p = \frac 1{14}$

Hence, the sea turtle has the least likelihood of 1/14

<h3>Animals with equal likelihood</h3>

The Blue fish and the Eels have the same frequency of 3

This means that animals have equal likelihood

<h3>The probability of seeing each animal</h3>

We have:

Blue fish = 3

Yellow fish = 7

Sea turtle = 1

Eels = 3

Express as probability

Blue fish = 3/14

Yellow fish = 7/14

Sea turtle = 1/14

Eels = 3/14

Express the fractions as decimals

Blue fish = 0.214

Yellow fish = 0.500

Sea turtle = 0.071

Eels = 0.214

So, their likelihoods are:

Blue fish = Equally likely

Yellow fish = Certainly likely

Sea turtle = Unlikely

Eels = Equally likely