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3 years ago

Did I do this correct???

Mathematics

1 answer:

kondor19780726 [428]3 years ago

6 0

The answer is actually D. Since 2.5 is a side of each tiny block, there is 3 sides that you are going to multiply together. There is 5,2 and 4 because we are multiplying the length,width and side. So the length is 2.5*5=12.5 which was correct. The width is 2.5*4=10 which you had but you crossed it out. Then lastly you are looking for the side of the shape. 2.5*2=5. Now that I have everything I just need to multiply everything together. 12.5*10*5=625 in³. I hope this helped you!

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_____8x^2+14x+3=0______

andriy [413]

Answer:

x= - $\frac{1}{4}$ , x = - $\frac{3}{2}$

Step-by-step explanation:

8 $x^{2}$ +14x+3=0

(4x+1)(2x+3)

x= - $\frac{1}{4}$ , x = - $\frac{3}{2}$

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3 years ago

How many solutions does this equation have? –2 − 10z = –4 − 10z

Katarina [22]

Answer:

No solutions

Step-by-step explanation:

To find out how many solutions there are you must solve:

- 2 - 10z = - 4 - 10z

Add 10z to both sides:

-2 = -4

Since the two terms are different from one another, that means that there are no solutions for this equation.

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3 years ago

Y varies directly as x and y=21 when x=6. determine the value of y when x=14

Hitman42 [59]

Answer:

y = 49

Step-by-step explanation:

Given y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 21 when x = 6 , then

21 = 6k ( divide both sides by 6 )

3.5 = k

y = 3.5x ← equation of variation

When x = 14 , then

y = 3.5 × 14 = 49

6 0

2 years ago

You want to determine the number of city residents who want to have 38th Street repaved. you randomly survey 15 residents who li

galina1969 [7]

Yes, because 12 out of 15 want the street repaved, 12 divided by 15 equals 0.8 and that would be turned into a percent.

4 0

3 years ago

a student ran out of time on a multiple choice exam and randomly guess the answers for two problems each problem have four answe

katen-ka-za [31]

Answer:

The probability that he answered neither of the problems correctly is 0.0625.

Step-by-step explanation:

We are given that a student ran out of time on a multiple-choice exam and randomly guess the answers for two problems each problem have four answer choices ABCD and only one correct answer.

Let X = Number of problems correctly answered by a student.

The above situation can be represented through binomial distribution;

$P(X=r)=\binom{n}{r}\times p^{r}\times (1-p)^{n-r};x=0,1,2,3,....$

where, n = number of trials (samples) taken = 2 problems

r = number of success = neither of the problems are correct

p = probability of success which in our question is probability that

a student answer correctly, i.e; p = $\frac{1}{4}$ = 0.75.

So, X ~ Binom(n = 2, p = 0.75)

Now, the probability that he answered neither of the problems correctly is given by = P(X = 0)

P(X = 0) = $\binom{2}{0}\times 0.75^{0}\times (1-0.75)^{2-0}$

= $1 \times 1\times 0.25^{2}$

= 0.0625

6 0

4 years ago