Answer:
Q1) ans-16%
Q2) ans-50%
Q3) ans- 16%
Q4) yes, I think the question 3 and 1 are same
Answer:
9.72
Step-by-step explanation:
s1 = 10.6383 ; s2 = 5.21289
x1 = 147.583 ; x2 = 136.417
n1 = 12 ; n2 = 12
df1 = n1 - 1 = 12 - 1 = 11
df2 = n2 - 1 = 12 - 1 = 11
The test statistic :
(x1 - x2) / sqrt[(sp²/n1 + sp²/n2)]
Pooled variance = Sp² = (df1*s1² + df2*s2²) ÷ (n1 + n2 - 2)
Sp² = ((11*10.6383) + (11*5.21289)) / 22 = 7.926
Test statistic, T* :
(147.583 - 136.417) / √(7.926 * (1/12 + 1/12))
11.166 / √(7.926 * (1/6)
11.166 / √1.321
11.166 / 1.1493476
T* = 9.7150766
Test statistic = 9.72
Answer:
And the best option for this case would be:
a. (17.5, 21.7)
Step-by-step explanation:
Information given
represent the sample mean
population mean
represent the population deviation
n=42 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
(1)
The degrees of freedom, given by:
Since the Confidence is 0.98 or 98%, the significance would be 
and 
, and the critical value would be 
Replacing we got:
And the best option for this case would be:
a. (17.5, 21.7)
Simplify the following:
-5×1×11×4
-5×1 = -5:
-5×11×4
-5×11 = -55:
-55×4
-55×4 = -220:
Answer: -220
Answer:
(xy - 4)(xy + 4).
Step-by-step explanation:
The is the difference of 2 squares.
a^2 - b^2 = (a - b)(a + b: so we have:
x^2y^2 - 16 = (xy - 4)(xy + 4)
