Turn y - 4 = -2/3(x - 6) into a linear equation.
y - 4 = -2/3(x - 6)
y - 4 = -2/3x + 4
+4 +4
y = -2/3x + 8
The equation that is perpendicular to y = -2/3x + 8 is y = 3x + 4 as shown in the image below using a graph.
0=2-3y+12x how do you solve this problem
1 answer:
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Step-by-step explanation:
r² (q + bx) = ax - p
qr² + bxr² = ax - p
qr² + p = ax - bxr²
qr² + p = x (a - br²)
I am not sure is you are supposed to solve or rewrite but for solving its this picture, tell me if its rewriting the problem and ill give you that as well!
