Answer:
The correct answer is Adam rowed faster in the men's 500-meter kayak race.
Step-by-step explanation:
To find the speed he rowed in both races, you need to divide the distance of the race by the time it took him to finish. In the first race, he rowed 500 meters and did it in a time of 1 minute 37.9 seconds, so the speed in that race would be 
or approximately 5.10725 meters per second. In the second race, Adam rowed a distance of 1000 meters and did it in a time of 3 minutes 28.2 seconds, which means his speed in that race would be 
or approximately 4.80307 meters per second. Since his speed in the first race was faster than his speed in the second race, Adam rowed faster in the first race would be the correct answer.
Answer:
Equation with variable
Step-by-step explanation:
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
Answer: 360 miles per hour…………………
For number 30 its 3
10
for 34 its 2
1/3
