Question

Using the same algorithm:

Answer 1

Answer:

• let the number be x:

$• { \tt{ \dashrightarrow \: 2(x + 2)}}$

$• \dashrightarrow{ \tt{2x + 1}}$

$• \dashrightarrow{ \tt{ 2x + 1 = 21}} \\ \\ { \tt{2x = 20}} \\ \\ • \: { \boxed{ \tt{output : \: \: x = 10 \: \: }}}$

Answer 2

Let input be x

$\\ \bull\tt\dashrightarrow 2(x+2)-3=21$

$\\ \bull\tt\dashrightarrow 2(x+2)=21+3$

$\\ \bull\tt\dashrightarrow 2(x+2)=24$

$\\ \bull\tt\dashrightarrow x+2=\dfrac{24}{2}$

$\\ \bull\tt\dashrightarrow x+2=12$

$\\ \bull\tt\dashrightarrow x=12-2$

$\\ \bull\tt\dashrightarrow x=10$