Answer:
A. Define boundaries
C. Deny access
D. Delay access
Explanation:
A barrier is a material or structure used to prevent or block access. Barriers can either be natural or structural and are used for many purposes usually for security reasons. The following are functions of barriers either natural or structural:
- Define areas of boundaries
- Delay or slow access. Example is the use of speed bumps to slow down vehicles.
- Provide access to entrances such as the use of gates
- Deny access to unauthorized personnel and allowing authorized personnel.
The correct answer: Yes, mobile-style apps can run in a personal computer's desktop.
That is possible by means of a desktop application called emulatator. An emulator like Bluestacks allows a personal computer to run mobile-style apps by acting as a virtual drive in the personal computer's harddisk.
Emulation is successful if the system requirements of the mobile-application is met by the personal computer's system attributes such as Random Access Memory abundance, Random Access Memory speed, Processing speed (in some cases core abundance e.g. core 2) etc.
Some mobile-applications do not work in the personal computer's desktop, however, if this application requires platform specific functions such as mobile device's network provider etc.
The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}
