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zzz [600]
3 years ago
12

Please Help!! Digital Information Technology Class!!

Computers and Technology
2 answers:
Rama09 [41]3 years ago
6 0
It’s probably GUI??.
klemol [59]3 years ago
3 0

Answer:

It's peer-to-peer

Explanation:

You might be interested in
A _____ is a form of Web conferencing that uses streaming media technologies to broadcast video and/or audio over the Internet f
ra1l [238]

Answer:

Webcast

Explanation:

Webcast is the live broadcast of a video or audio feed from your event or conference harnessing the internet. Webcast is a media presentation of an event circulated over the internet by using media technology to distribute a single source to various viewers.

Generally,  webcast is briefly defined as broadcasting over the internet. The broadcast might not be specifically live  . One can capture the video or the audio he or she wants to publish and publish it online anywhere. Webcast allow your viewers to remain engage as if they are face to face with the broadcaster.

Webcasting is a a great tools that has been used by various multinational and company to reach wide range of audience . This web based broadcast can even provide opportunity for audience to ask question and even provide answers in real time.

4 0
3 years ago
Read 2 more answers
Specific Instructions
Goryan [66]

In the most common use of the term, a class can be seen as a blueprint used to create objects. In other words, object(s) are created from a class in Java.

<h3>Creating a Class</h3><h3>Code:</h3>

import java.util.*;

class Card{

 private String suit;

 private int value;

 public Card(String s,int v){

   suit = s;

   value = v;

 }

 public String getSuit(){

   return suit;

 }

 public int getValue(){

   return value;

 }

 public void display(){

   System.out.println(value+"("+suit+")");

 }

}

class Deck{

 private ArrayList<Card> deck;

 private ArrayList<Card> drawn;

 public Deck(){

   deck = new ArrayList<Card>();

   drawn = new ArrayList<Card>();

   String[] arr = {"Club","Spade","Heart","Diamond"};

   for(String s : arr){

     for(int i=1;i<=13;i++){

       deck.add(new Card(s,i));

     }

   }

 }

 public void draw(){

   drawn.add(deck.get(0));

   deck.remove(0);

 }

 public void draw(int N){

   if(N > deck.size()){

     N = deck.size();

   }

   for(int i=0;i<N;i++){

     draw();

   }

 }

 public void showDrawn(){

   for(Card c : drawn){

     c.display();

   }

 }

 public void shuffle(){

   Collections.shuffle(deck);

 }

 public void restore(){

   restore(drawn.size());

 }

 public void restore(int N){

   if(N > drawn.size()){

     N = drawn.size();

   }

   for(int i=0;i<N;i++){

     deck.add(drawn.get(0));

     drawn.remove(0);

   }

 }

 public void showDeck(){

   for(Card c : deck){

     c.display();

   }

 }

}

class Test{

 public static void main(String[] args){

   Deck d = new Deck();

   System.out.println("Original deck\n");

   d.showDeck();

   d.draw(8);

   System.out.println("\nDeck after drawing 8 cards\n");

   d.showDeck();

   d.shuffle();

   System.out.println("\nDeck after shuffling\n");

   d.showDeck();

   d.restore();

   System.out.println("\nDeck after restoring cards\n");

   d.showDeck();

 }

}

<h3>Test Output:</h3>

C:\Users\hp\Desktop>java Test

Original deck

1(Club)

2(Club)

3(Club)

4(Club)

5(Club)

6(Club)

7(Club)

8(Club)

9(Club)

10(Club)

11(Club)

12(Club)

13(Club)

1(Spade)

2(Spade)

3(Spade)

4(Spade)

5(Spade)

6(Spade)

7(Spade)

8(Spade)

9(Spade)

10(Spade)

11(Spade)

12(Spade)

13(Spade)

1(Heart)

2(Heart)

3(Heart)

4(Heart)

5(Heart)

6(Heart)

7(Heart)

8(Heart)

9(Heart)

10(Heart)

11(Heart)

12(Heart)

13(Heart)

1(Diamond)

2(Diamond)

3(Diamond)

4(Diamond)

5(Diamond)

6(Diamond)

7(Diamond)

8(Diamond)

9(Diamond)

10(Diamond)

11(Diamond)

12(Diamond)

13(Diamond)

<h3>Draw action:</h3>

9(Club)

10(Club)

11(Club)

12(Club)

13(Club)

1(Spade)

2(Spade)

3(Spade)

4(Spade)

5(Spade)

6(Spade)

7(Spade)

8(Spade)

9(Spade)

10(Spade)

11(Spade)

12(Spade)

13(Spade)

1(Heart)

2(Heart)

3(Heart)

4(Heart)

5(Heart)

6(Heart)

7(Heart)

8(Heart)

9(Heart)

10(Heart)

11(Heart)

12(Heart)

13(Heart)

1(Diamond)

2(Diamond)

3(Diamond)

4(Diamond)

5(Diamond)

6(Diamond)

7(Diamond)

8(Diamond)

9(Diamond)

10(Diamond)

11(Diamond)

12(Diamond)

13(Diamond)

<h3 /><h3>Shuffling action:</h3>

12(Diamond)

8(Spade)

4(Spade)

6(Diamond)

10(Spade)

13(Club)

7(Heart)

13(Heart)

7(Diamond)

9(Heart)

11(Diamond)

5(Heart)

8(Diamond)

9(Diamond)

3(Spade)

13(Spade)

4(Heart)

2(Heart)

3(Heart)

5(Diamond)

11(Heart)

11(Club)

10(Club)

9(Club)

3(Diamond)

4(Diamond)

6(Spade)

9(Spade)

10(Heart)

11(Spade)

5(Spade)

12(Spade)

1(Spade)

6(Heart)

12(Heart)

13(Diamond)

1(Heart)

2(Diamond)

1(Diamond)

7(Spade)

12(Club)

10(Diamond)

2(Spade)

8(Heart)

  • Restore action

12(Diamond)

8(Spade)

4(Spade)

6(Diamond)

10(Spade)

13(Club)

7(Heart)

13(Heart)

7(Diamond)

9(Heart)

11(Diamond)

5(Heart)

8(Diamond)

9(Diamond)

3(Spade)

13(Spade)

4(Heart)

2(Heart)

3(Heart)

5(Diamond)

11(Heart)

11(Club)

10(Club)

9(Club)

3(Diamond)

4(Diamond)

6(Spade)

9(Spade)

10(Heart)

11(Spade)

5(Spade)

12(Spade)

1(Spade)

6(Heart)

12(Heart)

13(Diamond)

1(Heart)

2(Diamond)

1(Diamond)

7(Spade)

12(Club)

10(Diamond)

2(Spade)

8(Heart)

1(Club)

2(Club)

3(Club)

4(Club)

5(Club)

6(Club)

7(Club)

8(Club)

You can learn more about creating a class here brainly.com/question/10410845

6 0
2 years ago
In Java, write a AllDigitsOdd program that has a method called allDigitsOdd that takes an integer and returns whether every digi
yan [13]

Answer:

Hi there! The solution for this problem can be implemented a number of ways. Please find my solution below along with the explanation.

Explanation:

The prompts are fairly easily implemented using the Scanner class in Java for user input. In the allDigitsOdd function, we can perform a Math operation on the number being passed into the function to determine the number of digits in the number. We use the log10 function to do this and convert the double value returned to int. This is calculated in the code below as:  "(int)(Math.log10(number) + 1); ". Once we have the number of digits, we write a simple loop to iterate over each digit and perform a modulus function on it to determine if the digit is odd or even. I have declared 2 variables call odd and even that get incremented if the mod function (%) returns a 1 or a 0 respectively. Finally, the result is displayed on the screen.

AllDigitsOdd.java

import java.util.Scanner;

import java.lang.Math;

public class AllDigitsOdd {

 public static void main(String args[]) {

   // print main menu for user selection

   System.out.println("Please enter a number");

   Scanner scan = new Scanner(System.in);

   int selection = scan.nextInt();

   if (allDigitsOdd(selection)) {

     System.out.println("All numbers are odd");

   } else {

     System.out.println("All numbers are not odd");

   }

 }

 public static boolean allDigitsOdd(int number) {

   int digits = (int)(Math.log10(number) + 1);

   int even = 0;

   int odd = 0;

   for (int index = 1; index <= digits; index++) {

       if ((int)(number / Math.pow(10, index - 1)) % 10 % 2 == 0) {

         even += 1;

       } else {

         odd += 1;

       }

   }

   if (even == 0 && odd > 0) {

     return true;

   } else {

     return false;

     //if (odd > 0 && even == 0) {

     //  return true;

     //}

   }

 }

}

8 0
3 years ago
What feature is required to collect the number of comments users posted to a web page?
adell [148]

Custom Metric

Explanation: custom metrics can produce more flexible and more readable custom reports and as such are a convenient way to track your most important metrics.

6 0
3 years ago
Exercise 1-12 <br> This information is for Windsor, Inc. For the year ended December 31, 2017
Agata [3.3K]

Answer:

Please check the attachment.

Explanation:

Net change in cash, is the net increase in the cash from previous year which is 11900 here, and since the cash in hand is 17200, the net increment is 17200-11900 = 5300 from past year.

And the Cash forecast depends upon cash in hand, and which is 17200, and this is while disregarding future profit.

Rest of the details are in the file attached.

Download xlsx
8 0
3 years ago
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