16m^4 - n^4
= (4m^2 + n^2)(4m^2 - n^2)
= (4m^2 + n^2) (2m + n)(2m - n)
hi
u0 = 64 with u(n+1) = un *0.75
u3 = 64 *0.75^3 = 27
sum is : 64 * ( 0.75^4 -1) / 0.75-1 = 175
manual proof : 64 + 48+36+27 = 175
Answer: m∠ATC = 54°
Step-by-step explanation:
Ok, we know that:
m∠ATB = 20° and m∠BTD = 72°
then we must have that the angle between A and D, is equal to the sum of the angles between A and B, and B and D, or:
m∠ATD = m∠ATB + m∠BTD = 20° + 72° = 92°
Now, we also know that m∠CTD = 38°
And the angle:
m∠ATC will be equal to the angle between A and D, minus the angle between C and D, or:
m∠ATC = m∠ATD - m∠CTD = 92° - 38° = 54°
The ratio of that question is 7:12
