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3 years ago

(9+4c)+(2+3x) add timed so hurry!

Mathematics

1 answer:

Luba_88 [7]3 years ago

5 0

Answer: 3x + 4c + 11

Step-by-step explanation: Combine like terms.

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Dose anyone know this question I will give brainless bc I dont know this

Scrat [10]

Answer:

3.5

Step-by-step explanation:

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3 years ago

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Lipika reads a book 7/4 hours everyday. She reads the entire book in 6 days. How many hours in all were required by her to read

enyata [817]

Answer:

7/4 x 6 = 1.75 x 6 = 10.5 hours (or) 10 1/2 hours

Step-by-step explanation:

The equation says it all.

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3 years ago

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“the difference between five times a number and twice that number” ?

Gekata [30.6K]

Answer:Let

x-----------> the number

we know that

The expression "the difference between five times a number and twice that number" is equal to

5x-2x

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the answer is

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3 years ago

Use mathematical induction to prove

Alex17521 [72]

$Prove\ that\ the\ assumption \is \true for\ n=1\\1^3=\frac{1^2(1+1)^2}{4}\\ 1=\frac{4}{4}=1\\$

Formula works when n=1

Assume the formula also works, when n=k.

Prove that the formula works, when n=k+1

$1^3+2^3+3^3...+k^3+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k+1)^2}{4}+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k^2+2k+1)}{4}+(k+1)^3=\frac{(k^2+2k+1)(k^2+4k+4)}{4} \\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+4k^3+4k^2+2k^3+8k^2+8k+k^2+4k+4}{4}\\\\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+2k^3+k^2}{4}+\frac{4k^3+12k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+6k^3+13k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\$

Since the formula has been proven with n=1 and n=k+1, it is true. $\square$

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2 years ago

What is the value of |45-75|

Masteriza [31]

The answer is 45 because I just had this question

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4 years ago

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