Question

which point lies outside the circle with equation (x - 2) + (y + 3) = 4 (1, -4 ) ( 0, -3 ) ( 2, 0 ) (2, -4 )

Answer 1

Answer:

The point (2,0) is outside the circle

Step-by-step explanation:

we have

$(x-2)^{2}+(y+3)^{2}=4$

$(x-2)^{2}+(y+3)^{2}=2^{2}$

This is the equation of a circle with center at (2,-3) and radius equal to 2 units

Using a graphing tool

Plot the circle and the given points and verify if the point lie outside  the circle

we have

$(1, -4 ),(0, -3),(2, 0),(2,-4)$

so

The point (2,0) is outside the circle

see the attached figure