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3 years ago

100 POINTS plz dont answer unless you know how to solve this.

Mathematics

1 answer:

Alexandra [31]3 years ago

6 0

Answer:

31.9 mi

Step-by-step explanation:

AC/sin(angleABC) = AB/sin(angleACB)

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Fiona wrote out the description of each step for her multiplication of the binomial and trinomial (2x – 3)(5x2 – 2x + 7).

Arte-miy333 [17]

I just took the test and the answer is step 2.

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3 years ago

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Write the equation that passes through the given point and has the slope indicated: (1, -3); with slope (-3/5)

TiliK225 [7]

Answer:

y = -3/5x - 12/5

Step-by-step explanation:

The equation I'm going to give is going to be in slope-intercept form. If you need it in point-slope, I can do so in an edit or the comments.

Slope-intercept form is: y = mx + b where m is the slope, b is the y-intercept.

So let's plug in our given slope:

y = -3/5x + b

Using this, we now plug in our x- and y-coordinates from the given point to solve for b.

-3 = -3/5(1) + b

-3 = -3/5 + b

Add 3/5 to both sides to isolate variable b.

-3 + 3/5 = b

-15/5 + 3/5 = b

-12/5 = b

Plug this new info back into the original equation and your answer is

y = -3/5x - 12/5

6 0

3 years ago

Can someone tell me what 2 to the power of 6 is

Ira Lisetskai [31]

${2}^{6} = 64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2$

8 0

3 years ago

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2 bags of cat food cost $8.50, how much would 5 bags of cat food cost ?

luda_lava [24]

Answer:

$42.05

Step-by-step explanation:

First do $8.50/2=4.25

This means that one bag of cat food is $4.25

Now you multiply 5*4.25=$21.25,

I hope this helps and is correct!

8 0

3 years ago

find the standard form of equation of a line perpendicular to 4X plus 5Y equals 40 that includes the point -10, -3

snow_tiger [21]

The equation of line in standard form is 5x - 4y = -38

Solution:

Given that we have to find the equation of line perpendicular to 4x + 5y = 40 that includes the point (-10, -3)

The equation of line in slope intercept form is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given equation of line is:

4x + 5y = 40

Rearranging to slope intercept form, we get

5y = -4x + 40

$y = \frac{-4}{5}x + \frac{40}{5}\\\\y = \frac{-4}{5}x + 8$

On comparing the above equation with eqn 1,

$m = \frac{-4}{5}$

We know that product of slope of line and slope of line perpendicular to given line is equal to -1

Therefore,

$\frac{-4}{5} \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{5}{4}$

Now find the equation of line with slope 5/4 and passing through (-10, -3)

Substitute $m = \frac{5}{4}$ and (x, y) = (-10, -3) in eqn 1

$-3 = \frac{5}{4}(-10) + c\\\\-3 = \frac{-25}{2} + c\\\\c = -3 + \frac{25}{2}\\\\c = \frac{-6 + 25}{2}\\\\c = \frac{19}{2}$

Substitute $c = \frac{19}{2}$ and $m = \frac{5}{4}$ in eqn 1

$y = \frac{5}{4}x + \frac{19}{2}$

The standard form of an equation is Ax + By = C

Therefore,

$\frac{5}{4}x - y = -\frac{19}{2}\\\\\frac{5x - 4y}{4} = \frac{-19}{2}\\\\5x - 4y = -38$

Thus the equation of line in standard form is found

4 0

3 years ago