Answer:
a). Area of the parallelogram = 8 cm²
b). Area of both the triangles = 4 cm²
Step-by-step explanation:
a). Area of the given parallelogram ABCD = Base × Height
= DC × (Vertical distance between
AB and DC)
= 9 × 
= 8 ft²
b). If we decompose this parallelogram into two triangles ΔABC and ADC by a diagonal AC,
Area of both the triangles will be equal.
(Since, diagonal of a parallelogram divides the parallelogram into two equal triangles)
Therefore, area of ΔABC = Area of ΔADC = 4 ft²
Isolate the x. First, multiply 2 to both sides
-x/2(2) < 4(2)
-x < 4(2)
-x < 8
Isolate the x. Divide - 1 to both sides (because you are dividing a negative number, flip the sign).
-x/ -1 < 8/-1
x > -8 is your answer
hope this helps
108 for one interior angle is my answer. not sure if it's right tho
(1+x^2)^8
=(1+8x^2+8*7/(1*2)x^4+8*7*6/(1*2*3)x^6+8*7*6*5/(1*2*3*4)x^8+....)
=1+8x^2+28x^4+56x^6+70x^8+....)
For x<1, higher power terms diminish in value, hence we can approximate powers of numbers.
1.01=(1+0.1^2) => x=0.1 in the above expansion
(1.01)^8
=1+8(0.1^2)+28(0.1^4)+56(0.1^6) [ limited to four terms, as requested]
=1+0.08+0.0028+0.000056 (+0.00000070)
=1.082856 (approximately)
Answer:
1.548 gallons
Step-by-step explanation:
Length of the rectangular wall = 25.1 ft.
Width of the rectangular wall = 18.5 ft.
Area of the rectangular wall = length * width = 25.1 * 18.5
= 464.35 square feet
300 square feet wall can be painted using 1 gallon of paint.
=> 1 square feet wall can be painted using ![\[\frac{1}{300}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B1%7D%7B300%7D%5C%5D)
gallon of paint.
=> 464.35 square feet wall can be painted using ![\[\frac{1}{300} * 464.35\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B1%7D%7B300%7D%20%2A%20464.35%5C%5D)
gallon of paint.
= 1.548 gallons of paint
