1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hjlf
3 years ago
10

​A manager wants to know if the mean productivity of two workers is the same. For a random selection of 30 hours in the past​ mo

nth, he compares the number of items produced by each worker in that hour.A. The data should be treated as paired samples. Each pair consists of an hour in which the productivity of the two workers is compared.B. The data should be treated as paired samples. Each pair consists of two hours in which the number of items produced is compared.C. The data should be treated as independent samples because the samples are random.
Mathematics
1 answer:
vekshin13 years ago
7 0

Answer:

A.The data should be treated as paired samples. Each pair consists of an hour in which the productivity of the two workers is compared.

Explanation:

If the mean productivity of two workers is the same.

For a random selection of 30 hours in the past month, the manager compares the number of items produced by each worker in that hour.

There are two samples and the productivity of the two men is paired for each hour.

You might be interested in
What is the simplest form of 1764
vova2212 [387]

Answer:

42

Step-by-step explanation:

Do the math:)

6 0
3 years ago
HELP PLEASE!! Alita is 2 times as old as Jiro. Jiro is 4 years younger than Erik. Erik is 1/3 as old as dawn. The sum of all the
Aleonysh [2.5K]

Answer:

a cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speed

5 0
3 years ago
Read 2 more answers
What is the median of the data set? <br> {10, 15, 14, 14, 10, 10, 8, 18, 11, 12, 17, 16}
Alexus [3.1K]
The median of a data set is the 'middle number'. You can find the median by listing the given numbers from least to greatest (left to right) and finding the middle number.

8, 10, 10, 10, 11, 12, 14, 14, 15, 16, 17, 18

Cross one out on each side before getting to your last number that should be in the middle. 

The middle numbers are: 12 and 14. If it was only one number, we could already have the answer, but since it is two numbers in the middle, we need to add them up and divide by 2. 

12 + 14 = 26
26 ÷ 2 = 13

So, the median of the data set is: 13.
6 0
3 years ago
The Suarez family paid $12.75 for 3 movie tickets. How much would they have paid for 12 tickets?
77julia77 [94]

Answer:

51 dollars

Step-by-step explanation:

4 times 12.75 =51

8 0
3 years ago
Read 2 more answers
for every 5 people who bought $9.75 tickets to the football game, 3 people bought $14.50 tickets. If each of 35 people bought a
Readme [11.4K]

9514 1404 393

Answer:

  21

Step-by-step explanation:

The number who bought expensive tickets is 3/5 of the number who bought cheap tickets.

  (3/5)(35) = 21

21 people bought the more expensive ticket.

3 0
3 years ago
Read 2 more answers
Other questions:
  • Gavin is building a fence. He needs to put a post every feet. If a new segment of the fence has 15 new posts, using the last pos
    10·1 answer
  • Pls help me on this Jackson purchased a pack of game cards that was on sale for 22% off. The sales tax in his county is 6%. Let
    13·1 answer
  • Use the following function rule to find f(16.36).
    11·1 answer
  • Y= (x-9) (x+3)
    10·1 answer
  • Sam has
    13·2 answers
  • Order of Operation
    6·2 answers
  • 5% equals what fraction, in lowest terms?
    11·2 answers
  • En las olimpiadas de Matemática. Roció represen a su colegio. La prueba consistía en 60 problemas. Cada respuesta correcta valía
    10·1 answer
  • Helppp! asap! plsssss:)!
    9·1 answer
  • Write an equation based on the graph.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!