All categories

3 years ago

A quadrilateral has no pairs of parallel sides. what two shapes could it be

Mathematics

2 answers:

Katen [24]3 years ago

5 0

Answer:

Trapezium usually means a quadrilateral with no parallel sides.

Also kites have no parallel sides

Svetach [21]3 years ago

4 0

A trapezium I believe

You might be interested in

In 1999 there were 1647 daily and 7471 weekly newspapers published in the United States, as well as X other kinds of newspapers.

kompoz [17]

I'll do the math for this, it may take me a few minutes so i will update this comment with an answer in just a minute. I always get anxious when nobody replies kind of quickly as i feel it is being forgotten. So just a heads up i'm working on a answer!

4 0

3 years ago

-|-5| Is the answer greater than, less than, or equal to -5

ehidna [41]

Answer:

equal to

Step-by-step explanation:

3 0

3 years ago

Ali, Ben and Clare each played a game. Clare's score was seven times Ali's score. Ben's score was half of Clare's score. Write d

Lerok [7]

Answer:

The answer is 2 : 7 : 14

8 0

3 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

A water pump fills a swimming pool at a rate of 80

Nat2105 [25]

9514 1404 393

Answer:

5 hours

Step-by-step explanation:

The volume of the pool is ...

V = LWH

V = (10 ft)(8 ft)(5 ft) = 400 ft^3

At the given fill rate, the time it will take is ...

(400 ft^3)/(80 ft^3/h) = 5 h

It will take 5 hours for the pump to fill the pool.

3 0

3 years ago

Read 2 more answers